Find the vector form of the general solution of the given linear system Ax = b; then use that resu general solution of Ax = 0. + x2 + 2x3 6. + X3 -2 2x1 + x2 + 3x3 4 O The general solution of Ax = b is (x1, X2, X3) = ( – 2, 8, 0) + s( – 1, – 1, 1); and the general solution of Ax = 0 is (x1 , X2, X3) = ( – 2, 8, 0). O The general solution of Ax = b is (x1, X2, X3) = s( – 2, 8, 0) + ( – 1, – 1, 1); and the general solution of Ax = 0 is (x) , X2, X3) = s( – 1, – 1, 1). %3D O The general solution of Ax = b is(x1, x2, x3) = s( – 1, – 1, 1); and the general solution of Ax = 0 is (x1 , X2, X3) = ( – 2, 8, 0) + s( – 1, – 1, 1). O The general solution of Ax = bis (x1, X2, X3) = s(– 2, 8, 0) + ( – 1, – 1, 1); %3D

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Find the vector form of the general solution of the given linear system Ax = b; then use that result to find the vector form of the
general solution of Ax = 0.
+ x2
+ 2x3
6.
+
X3
-2
2x1
+ x2
+ 3x3
4
O The general solution of Ax = b is (x1, X2, X3) = ( – 2, 8, 0) + s( – 1, – 1, 1);
and the general solution of Ax = 0 is (x1 , X2, X3) = ( – 2, 8, 0).
O The general solution of Ax = b is (x1, X2, X3) = s( – 2, 8, 0) + ( – 1, – 1, 1);
and the general solution of Ax = 0 is (x) , X2, X3) = s( – 1, – 1, 1).
%3D
O The general solution of Ax = b is(x1, x2, x3) = s( – 1, – 1, 1);
and the general solution of Ax = 0 is (x1 , X2, X3) = ( – 2, 8, 0) + s( – 1, – 1, 1).
O The general solution of Ax = b is (x1, X2, X3) = s( – 2, 8, 0) + ( – 1, – 1, 1);
and the general solution of Ax = 0 is (x1 , X2, X3) = s( – 2, 8, 0).
O The general solution of Ax = b is (x1, X2, X3) = ( – 2, 8, 0) + s( – 1, – 1, 1);
and the general solution of Ax = 0 is (x1, x2, X3) = s( – 1, – 1, 1).
Transcribed Image Text:Find the vector form of the general solution of the given linear system Ax = b; then use that result to find the vector form of the general solution of Ax = 0. + x2 + 2x3 6. + X3 -2 2x1 + x2 + 3x3 4 O The general solution of Ax = b is (x1, X2, X3) = ( – 2, 8, 0) + s( – 1, – 1, 1); and the general solution of Ax = 0 is (x1 , X2, X3) = ( – 2, 8, 0). O The general solution of Ax = b is (x1, X2, X3) = s( – 2, 8, 0) + ( – 1, – 1, 1); and the general solution of Ax = 0 is (x) , X2, X3) = s( – 1, – 1, 1). %3D O The general solution of Ax = b is(x1, x2, x3) = s( – 1, – 1, 1); and the general solution of Ax = 0 is (x1 , X2, X3) = ( – 2, 8, 0) + s( – 1, – 1, 1). O The general solution of Ax = b is (x1, X2, X3) = s( – 2, 8, 0) + ( – 1, – 1, 1); and the general solution of Ax = 0 is (x1 , X2, X3) = s( – 2, 8, 0). O The general solution of Ax = b is (x1, X2, X3) = ( – 2, 8, 0) + s( – 1, – 1, 1); and the general solution of Ax = 0 is (x1, x2, X3) = s( – 1, – 1, 1).
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