Find the values of the constants C₁, A such that the function y(x) = C₁e satisfies to ODE with the IC: y(x)' + ay(x) = 0, y(0) = b. O C₁ can be arbitrary, λ = -a. O C₁ = b, λ =a C₁ can be arbitrary, λ = a. O C₁ = b, λ = -a. O C₁ = -b, A = a. O C₁ = -b, λ =-a.
Find the values of the constants C₁, A such that the function y(x) = C₁e satisfies to ODE with the IC: y(x)' + ay(x) = 0, y(0) = b. O C₁ can be arbitrary, λ = -a. O C₁ = b, λ =a C₁ can be arbitrary, λ = a. O C₁ = b, λ = -a. O C₁ = -b, A = a. O C₁ = -b, λ =-a.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![**Problem Statement:**
Find the values of the constants \( C_1 \), \( \lambda \) such that the function \( y(x) = C_1 e^{\lambda x} \) satisfies the ordinary differential equation (ODE) with the initial conditions:
\[ y(x)' + ay(x) = 0, \quad y(0) = b. \]
**Choices:**
- \( \circ \) \( C_1 \) can be arbitrary, \( \lambda = -a \).
- \( \circ \) \( C_1 = b, \lambda = a \).
- \( \circ \) \( C_1 \) can be arbitrary, \( \lambda = a \).
- \( \circ \) \( C_1 = b, \lambda = -a \).
- \( \circ \) \( C_1 = -b, \lambda = a \).
- \( \circ \) \( C_1 = -b, \lambda = -a \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F12c62ea9-2423-4a35-a6cd-74646c6bbd41%2F2e8575a7-2c0b-45ee-86cb-8e129e509992%2F02wfc23_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Find the values of the constants \( C_1 \), \( \lambda \) such that the function \( y(x) = C_1 e^{\lambda x} \) satisfies the ordinary differential equation (ODE) with the initial conditions:
\[ y(x)' + ay(x) = 0, \quad y(0) = b. \]
**Choices:**
- \( \circ \) \( C_1 \) can be arbitrary, \( \lambda = -a \).
- \( \circ \) \( C_1 = b, \lambda = a \).
- \( \circ \) \( C_1 \) can be arbitrary, \( \lambda = a \).
- \( \circ \) \( C_1 = b, \lambda = -a \).
- \( \circ \) \( C_1 = -b, \lambda = a \).
- \( \circ \) \( C_1 = -b, \lambda = -a \).
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