Find the values of b such that the function f(x)=x²+ bx + 59 has the given minimum value 10. +16 +20 +18 ±22 +14

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A: Since, we have f(x)=10-3x2(a)f(2)=10-3(2)2 ⇒f(2)=10-3(4)=10-12⇒f(2)=-2

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