Find the value of z so that -8' 1 -4 is in the set M= span 12 2 2 Enter the value below:

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Find values of z so that u is in the set M

To solve the problem, we need to find the value of \( z \) such that the vector 

\[
\mathbf{u} = 
\begin{bmatrix} 
-8 \\ 
z \\ 
12 \\ 
-6 
\end{bmatrix}
\]

is in the set given by the span of the vectors

\[
M = \text{span} \left\{ 
\begin{bmatrix} 
-4 \\ 
1 \\ 
2 \\ 
3 
\end{bmatrix}, 
\begin{bmatrix} 
0 \\ 
-4 \\ 
2 \\ 
-5 
\end{bmatrix}, 
\begin{bmatrix} 
0 \\ 
0 \\ 
-4 \\ 
2 
\end{bmatrix} 
\right\}.
\]

This means that the vector \(\mathbf{u}\) can be expressed as a linear combination of the vectors in the set \(M\). We need to determine the coefficients for each of the vectors in \(M\) such that when combined, they equal \(\mathbf{u}\).

The task is to solve for \(z\) and express \(\mathbf{u}\) as:

\[
a 
\begin{bmatrix} 
-4 \\ 
1 \\ 
2 \\ 
3 
\end{bmatrix} + 
b 
\begin{bmatrix} 
0 \\ 
-4 \\ 
2 \\ 
-5 
\end{bmatrix} + 
c 
\begin{bmatrix} 
0 \\ 
0 \\ 
-4 \\ 
2 
\end{bmatrix}
=
\begin{bmatrix} 
-8 \\ 
z \\ 
12 \\ 
-6 
\end{bmatrix}.
\]

Enter the value of \( z \) in the box provided:

\( z = \) \(\boxed{}\)
Transcribed Image Text:To solve the problem, we need to find the value of \( z \) such that the vector \[ \mathbf{u} = \begin{bmatrix} -8 \\ z \\ 12 \\ -6 \end{bmatrix} \] is in the set given by the span of the vectors \[ M = \text{span} \left\{ \begin{bmatrix} -4 \\ 1 \\ 2 \\ 3 \end{bmatrix}, \begin{bmatrix} 0 \\ -4 \\ 2 \\ -5 \end{bmatrix}, \begin{bmatrix} 0 \\ 0 \\ -4 \\ 2 \end{bmatrix} \right\}. \] This means that the vector \(\mathbf{u}\) can be expressed as a linear combination of the vectors in the set \(M\). We need to determine the coefficients for each of the vectors in \(M\) such that when combined, they equal \(\mathbf{u}\). The task is to solve for \(z\) and express \(\mathbf{u}\) as: \[ a \begin{bmatrix} -4 \\ 1 \\ 2 \\ 3 \end{bmatrix} + b \begin{bmatrix} 0 \\ -4 \\ 2 \\ -5 \end{bmatrix} + c \begin{bmatrix} 0 \\ 0 \\ -4 \\ 2 \end{bmatrix} = \begin{bmatrix} -8 \\ z \\ 12 \\ -6 \end{bmatrix}. \] Enter the value of \( z \) in the box provided: \( z = \) \(\boxed{}\)
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