Find the value of z if the area under a standard normal curve (a) to the right of z is 0.3228; (b) to the left of z is 0.1271; (c) between 0 and z, with z> 0, is 0.4890; and (d)between -zand z, with z> 0, is 0.9500.Click here to view page 1 of the standard normal distribution table.Click here to view page 2 of the standard normal distribution table. Areas under the Normal Curve01000203.04.05.0608090.00030.0004-3.4-3.4-3.3-3.2 0.0007 0.0007-3.1-3.00.00030.0003 0.00030.0005 0.00050.00060.00030.00030.00030.0004 0.0004 0.00040.000 0.00030.00020.0003 -3.30.0005 -3.20.00070.00050.0004 0.00040.0006 0.00060.00080.0013 0.0013 0.0013 0.0012 0.0012 0.0011 0.0011 0.001 0.0010 0.0010 -3.00.00060.0006 0.0005 0.00050.00100.00090.0009 0.0009 0.00080.00080.00080.0007-3.1-29-2.8-2.7-2.6-250.0019 0.00180.00180.00170.0016 0.00160.0015 0.0015 0.0014 0.0014 -290.0020 0.0019 -280.0030 0.0029 0.0028 0.0027 0.0026 -270.0040 0.0039 0.0038 0.0037 0.0036 -260.008 -250.0210.00260.00350.00470.00620.00250.00340.00450.0024 0.0023 0.00230.00330.0044 0.00430.0022 0.00210.0032 0.00310.00410.00600.0090.0057 0.00GS 0.0054 0.0052 0.0061 0.009--24 0.0082 0.0080-230.00780.0075 0.0073 0.00710.0069 0.0068 0.0066 0.0064 -240.0084 -230.0110 -220.01070.01040.01020.00990.00960.00940.00910.0089 0.0087-22-2.1-2.00.01390.01360.01320.0129 0.0125 0.01220.0119 0.01160.01130.01790.02280.0174 0.0170 0.0166 0.0162 0.0158 0.0154 0.01500.02220.0146 0.0143 -210.0183 -200.02170.02120.02070.01970.01920.0188-1.9 0.0287--18 0.03590.04460.02810.0274 0.0268 0.0262 0.0256 0.0250 0.02440.0329 0.03220.0090.0233 -1.90.0314 0.0307 0.0001 0.0294 -180.0067 -1.70.02390.03510.03440.03360.0418-1.70.0436 0.04270.0010.0392 0.0384 0.0375-1.60.05480.0537 0.0526 0.0516 0.05050.0650.0495 0.04850.04750.0465 0.0455 -1.6-1.5 0.06680.0643 0.0630 0.0618 0.06060.0594 0.0682 0.05710.0559 -1.50.0808 0.07930.00G8-1.2 0.11510.07350.08850.1131 0.1112 0.1093 0.1075 0.1066 0.1008 0.1020 0.1003 0.0085 -120.07640.0961 0.0034 0.0018 0.09010,0708 0.0604 0.0681 -140.08380.07780.0749-1.4-130.07210.08690.0830.0823 -130.1335 0.1314 0.1292 0.1271 0.125I 0.1230 0.12100.1446 0.1423-1.10.13570.1190 0.1170 -1.1-1.00.1587 0.15620.15390.15150.1492 0.14690.14010.1379 -1O-0.9 0.18410.21190.24200.18140.20000.2390.27090.30600.1788 0.1762 0.1736 0.17110.2061 0.2033 0.200G 0.1977 0.199 0.1922 0.1894 0.1867 -080.23580.1685 0.1660 0.1635 0.1611 -0.9-0.8-0.70.2327 0.2296 0.22660.2236 0.22060.21770.24830.2810 02776 -0.50.2148-0.70.6-0.50.27430.2676 0.2643 0.2611 0.2578 0.25-46 0.25140.21510.60.29810.3372 0.3336 0.33000.30850.30150.2946 0.2912 0.28770.2843-0.40.34460.34090.31210.3264 0.32280.36320.31920.3156-0.40.30.38210.3783 0.37450.37070.36690.35940.35570.3974 0.3Os0.43250.3520 0.34830.385903-0.2 0.42070.4168 0.41290.40900.4052 0.40130.3897-0.2-0.10.46020.45620.45220.44830.44430.44040.43640.42860.42470.4641 -0.0-0.1-0.00.50000.4900.49200.48800.48400.48010.47610.47210.4681.000102.03.04.05.06070809

Here, we have to find the area under the standard normal curve

Find the value of z if the area under a standard normal curve (a) to the right of z is 0.3228; (b) to the left of z is 0.1271; (c) between 0 and z, with z> 0, is 0.4890; and (d) between -z and z, with z> 0, is 0.9500. Click here to view page 1 of the standard normal distribution table

Find the value of z if the area under a standard normal curve (a) to the right of z is 0.3228; (b) to the left of z is 0.1271; (c) between 0 and z, with z> 0, is 0.4890; and (d) between -z and z, with z> 0, is 0.9500. Click here to view page 1 of the standard normal distribution table

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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