Find the value of x.

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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### Find the Value of x

Below is a problem that requires solving for the variable \( x \) in a right triangle. The triangle has the following side lengths:

- The length of one leg \( x \).
- The length of the other leg is \( 11 \).
- The hypotenuse is \( 13 \).

Here is how the problem and answer choices are displayed:

![Image: Right Triangle](RightTriangle.png)

**Diagram Explanation:** In the above diagram, the right triangle has one leg marked as \( x \), the other leg is \( 11 \) units, and the hypotenuse is \( 13 \) units.

**Question:** Find the value of \( x \).

**Answer Choices:**
1. \( x = 48 \)
2. \( x = 4\sqrt{3} \)
3. \( x = \sqrt{290} \)
4. \( x = 2 \)

**Correct Answer:** The selected answer is \( x = 48 \), which will be discussed in the solution section.

**Solution:**
To find the value of \( x \), we can use the Pythagorean theorem:

\[ a^2 + b^2 = c^2 \]

Here, \( a = x \), \( b = 11 \), and \( c = 13 \). Plugging in these values, we have:

\[ x^2 + 11^2 = 13^2 \]

Solving for \( x \):

\[ x^2 + 121 = 169 \]

\[ x^2 = 169 - 121 \]

\[ x^2 = 48 \]

\[ x = \sqrt{48} \]

Thus, the correct value of \( x \) is \( \sqrt{48} \), which is not exactly \( 48 \). Instead, it simplifies to approximately \( 6.93 \).

Therefore, the initially selected answer \( x = 48 \) is incorrect. The correct value, considering standard simplifications of square roots doesn't match any of the provided answer choices. The problem may have an error in its answer choices.

Make sure to verify and recalculate the steps or refer to alternative methods if discrepancies arise.
Transcribed Image Text:### Find the Value of x Below is a problem that requires solving for the variable \( x \) in a right triangle. The triangle has the following side lengths: - The length of one leg \( x \). - The length of the other leg is \( 11 \). - The hypotenuse is \( 13 \). Here is how the problem and answer choices are displayed: ![Image: Right Triangle](RightTriangle.png) **Diagram Explanation:** In the above diagram, the right triangle has one leg marked as \( x \), the other leg is \( 11 \) units, and the hypotenuse is \( 13 \) units. **Question:** Find the value of \( x \). **Answer Choices:** 1. \( x = 48 \) 2. \( x = 4\sqrt{3} \) 3. \( x = \sqrt{290} \) 4. \( x = 2 \) **Correct Answer:** The selected answer is \( x = 48 \), which will be discussed in the solution section. **Solution:** To find the value of \( x \), we can use the Pythagorean theorem: \[ a^2 + b^2 = c^2 \] Here, \( a = x \), \( b = 11 \), and \( c = 13 \). Plugging in these values, we have: \[ x^2 + 11^2 = 13^2 \] Solving for \( x \): \[ x^2 + 121 = 169 \] \[ x^2 = 169 - 121 \] \[ x^2 = 48 \] \[ x = \sqrt{48} \] Thus, the correct value of \( x \) is \( \sqrt{48} \), which is not exactly \( 48 \). Instead, it simplifies to approximately \( 6.93 \). Therefore, the initially selected answer \( x = 48 \) is incorrect. The correct value, considering standard simplifications of square roots doesn't match any of the provided answer choices. The problem may have an error in its answer choices. Make sure to verify and recalculate the steps or refer to alternative methods if discrepancies arise.
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