Find the value of x. Round to the nearest tenth. 37° 17.3 Show your work.

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
icon
Related questions
icon
Concept explainers
Topic Video
Question
Value of x?
---

### Geometry Unit 4: End of Unit Summary

#### Problem 5:
**Objective:** Find the value of \(x\). Round to the nearest tenth.

A right-angled triangle is shown with an acute angle of \(37^\circ\). The side opposite this angle is labeled \(x\), and the adjacent side is labeled \(17.3\).

**Triangle Diagram:**

```
         /|
        / |
     x /  | 17.3
      / 37°|
     /_____|
```

**Task:**
- Find the value of \(x\).
- Show your work in the provided field.

**Solution:**
- To find the value of \(x\), we will use trigonometric ratios. Specifically, we'll use the tangent function, which relates the opposite side and the adjacent side of a right triangle.

\[ \tan(37^\circ) = \frac{\text{opposite}}{\text{adjacent}} \]

Given:
- Opposite side = \(x\)
- Adjacent side = \(17.3\)

The equation becomes:
\[ \tan(37^\circ) = \frac{x}{17.3} \]

Solving for \(x\):
\[ x = 17.3 \times \tan(37^\circ) \]

Use a calculator to find \(\tan(37^\circ)\):
\[ \tan(37^\circ) \approx 0.7536 \]

Therefore:
\[ x = 17.3 \times 0.7536 \approx 13.0 \]

So, \(x \approx 13.0\) (rounded to the nearest tenth).

**Show Your Work:**
\[ x = 17.3 \times \tan(37^\circ) \]
\[ x \approx 17.3 \times 0.7536 \]
\[ x \approx 13.0 \]

---

**Scoring Rubric:**
- **0 pts:** Incomplete
- **1.5 pts:** Tier 3 Response
- **2 pts:** Between tier 2 and tier 3 Response
- **2.5 pts:** Tier 2 Response
- **3 pts:** Tier 1 Response

Points are awarded based on the completeness and accuracy of the solution.

---
Transcribed Image Text:--- ### Geometry Unit 4: End of Unit Summary #### Problem 5: **Objective:** Find the value of \(x\). Round to the nearest tenth. A right-angled triangle is shown with an acute angle of \(37^\circ\). The side opposite this angle is labeled \(x\), and the adjacent side is labeled \(17.3\). **Triangle Diagram:** ``` /| / | x / | 17.3 / 37°| /_____| ``` **Task:** - Find the value of \(x\). - Show your work in the provided field. **Solution:** - To find the value of \(x\), we will use trigonometric ratios. Specifically, we'll use the tangent function, which relates the opposite side and the adjacent side of a right triangle. \[ \tan(37^\circ) = \frac{\text{opposite}}{\text{adjacent}} \] Given: - Opposite side = \(x\) - Adjacent side = \(17.3\) The equation becomes: \[ \tan(37^\circ) = \frac{x}{17.3} \] Solving for \(x\): \[ x = 17.3 \times \tan(37^\circ) \] Use a calculator to find \(\tan(37^\circ)\): \[ \tan(37^\circ) \approx 0.7536 \] Therefore: \[ x = 17.3 \times 0.7536 \approx 13.0 \] So, \(x \approx 13.0\) (rounded to the nearest tenth). **Show Your Work:** \[ x = 17.3 \times \tan(37^\circ) \] \[ x \approx 17.3 \times 0.7536 \] \[ x \approx 13.0 \] --- **Scoring Rubric:** - **0 pts:** Incomplete - **1.5 pts:** Tier 3 Response - **2 pts:** Between tier 2 and tier 3 Response - **2.5 pts:** Tier 2 Response - **3 pts:** Tier 1 Response Points are awarded based on the completeness and accuracy of the solution. ---
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 2 images

Blurred answer
Knowledge Booster
Angles, Arcs, and Chords and Tangents
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, geometry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
Geometry
ISBN:
9781337614085
Author:
Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:
Cengage,
Elementary Geometry for College Students
Elementary Geometry for College Students
Geometry
ISBN:
9781285195698
Author:
Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:
Cengage Learning