Find the value of x. 7

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 26E
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## Geometry Problem: Finding the Value of \( x \)

### Question 4:
**Find the value of \( x \).**

### Diagram Explanation:
In the provided diagram (labeled 8), there is:

1. A circle with a secant and tangent intersecting outside the circle.
2. The secant segment measures 7 units, with an external segment of 5 units.
3. An intersecting tangent is marked with a length of \( x \).
4. Another segment within the circle, directly opposite the internal segment of the secant, is marked 4 units.

The task is to find the unknown length \( x \).

Using the Secant-Tangent Theorem: If a secant and a tangent intersect outside a circle, the square of the length of the tangent segment is equal to the product of the lengths of the entire secant segment and its external part.

Based on this theorem:
\[ x^2 = 5 \times (5 + 7) \]
\[ x^2 = 5 \times 12 \]
\[ x^2 = 60 \]
\[ x = \sqrt{60} \]
\[ x = 2\sqrt{15} \]

So, the value of \( x \) is \( 2\sqrt{15} \).
Transcribed Image Text:## Geometry Problem: Finding the Value of \( x \) ### Question 4: **Find the value of \( x \).** ### Diagram Explanation: In the provided diagram (labeled 8), there is: 1. A circle with a secant and tangent intersecting outside the circle. 2. The secant segment measures 7 units, with an external segment of 5 units. 3. An intersecting tangent is marked with a length of \( x \). 4. Another segment within the circle, directly opposite the internal segment of the secant, is marked 4 units. The task is to find the unknown length \( x \). Using the Secant-Tangent Theorem: If a secant and a tangent intersect outside a circle, the square of the length of the tangent segment is equal to the product of the lengths of the entire secant segment and its external part. Based on this theorem: \[ x^2 = 5 \times (5 + 7) \] \[ x^2 = 5 \times 12 \] \[ x^2 = 60 \] \[ x = \sqrt{60} \] \[ x = 2\sqrt{15} \] So, the value of \( x \) is \( 2\sqrt{15} \).
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