find the value of the following zero sum game: (; ::). 3 7 6 5 0 6

Q: Given P(A) = 0.34, P(A and B) = 0.20, P(A or B) = 0.55, what is P(B)?

A: We have given that,  P(A) = 0.34, P(A and B) = 0.20, P(A or B) = 0.55, then, We will find the value…

Q: P(A)=0.45, P(B)=0.58, and P(B|A)= 0.05. What is P(A and B)?

A: Given that  P(A)=0.45, P(B)=0.58, and P(B|A)= 0.05

Q: -3(w+1)+8(w-3)=-5w+9+6w

A:

Q: If P(A or B)= 0.8, P(A)= 0.5 and P(A and B) = 0.25, find P(B)

A:

Q: 7(n-2)=28

A: Solving for n

Q: If P(A) = 0.5 and P(B) = 0.80, then P(A or B) must be 0.95.   TRUE or FALSE

A: From the provided information, P (A) = 0.5 and P (B) = 0.80

Q: If P(A) =0.7, P(B) = 0.1 and A and B are mutually exclusive, find  P(A and B)

A: From the provided information, P (A) = 0.7, P (B) = 0.1

Q: L(P-5)0

A: Explanation of the answer is as follows

Q: 4(5+6)=

A: Given: 4(5+6)=

Q: Given P(A) = 0.40, P(B) = 0.35, and P(A and B) = 0.12, what is P(A or B)?

A: Formula : P(A or B) = P(A) + P(B) - P(A n B)

Q: Given P(A) = 0.01, P(B) = 0.88 , and P(B|A)=0.34 , what is P(A and B)?

A: Given: P(A)=0.01P(B)=0.88P(BA)=0.34 The objective is to find the probability of P(A∩B).

Q: If P(A) 0.3 , P(B) = 0.8 and P(A or B) = 0.9 Find P(A and B).

A:

Q: d.x V1– x10

A:

Q: Find P(A and B) P(A) = 0.7 P(B)=0.2 P(A or B)= 0.4

A: Given, P(A) = 0.7 P(B)=0.2 P(A or B)= 0.4

Q: If P(A) = 0.3, P(B) = 0.8, and P(A or B) = 0.9, find P(A and B). P(A and B) =

A:

Q: If P(A) = 0.3, P(B) = 0.7, and P(A and B) = 0.2, find P(A or B). P (A or B) =

A: Given information- P(A) = 0.3 P(B) = 0.7 P(A and B) = 0.2 We have to find P(A or B)-

Q: -4 -4 -6 -7 -12, 9-( X

A:

Q: 1) (-2) + 3

A: Solving this we have

Q: If​ P(A or ​B)equals=0.70.7​, ​P(A)equals=0.30.3​, and​ P(A and ​B)equals=0.250.25​, find​ P(B).

A: The given information isP (A or B) =0.70P (A) =0.30P (A and B) =0.25