Find the value of the derivative (if it exists) at the indicated extremum. 4√6 (-4, 416) f(x) = - - 3x√x + 2 -2 10 5 сл -5 -10 2 4

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Fast pls solve this question correctly in 5 min pls I will give u like for sure Anu
Step 2
Factor and simplify.
f'(x) =
= ²(x + 2)=¹/2 √x + 2(
-1/2
=
= ²³²(x + 2)-1¹/² (
-3(
2√x + 2
)
+ 4)
>]
Transcribed Image Text:Step 2 Factor and simplify. f'(x) = = ²(x + 2)=¹/2 √x + 2( -1/2 = = ²³²(x + 2)-1¹/² ( -3( 2√x + 2 ) + 4) >]
Find the value of the derivative (if it exists) at the indicated extremum.
4√6
f(x) = - 3xVx + 2
-4
Step 2
Differentiate f(x) using the product rule.
f '(x) = – 3x 1/2
Factor and simplify.
10-
5
मैं
-5
-10
Step 1
The minimum and maximum of a function on an interval are the extreme values, or extrema (the singular form of extrema is extremum), of the function on the interval.
In the given problem, the extremum occurs when x = उ
The specified function is f (x) = −3x/x + 2 = −3x(x + 2) 1/2
2
0.5 ( x + 2)
4
-1
[2] +
+ (x + 2)1/2.
✓
-3)
Transcribed Image Text:Find the value of the derivative (if it exists) at the indicated extremum. 4√6 f(x) = - 3xVx + 2 -4 Step 2 Differentiate f(x) using the product rule. f '(x) = – 3x 1/2 Factor and simplify. 10- 5 मैं -5 -10 Step 1 The minimum and maximum of a function on an interval are the extreme values, or extrema (the singular form of extrema is extremum), of the function on the interval. In the given problem, the extremum occurs when x = उ The specified function is f (x) = −3x/x + 2 = −3x(x + 2) 1/2 2 0.5 ( x + 2) 4 -1 [2] + + (x + 2)1/2. ✓ -3)
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