Please answer Tutorial ExerciseFind the value of the derivative (if it exists) at the indicated extremum.(금)-4 4V6f(x) = - 3xVx + 210아-4-24-5- 10Step 1The minimum and maximum of a function on an interval are the extreme values, or extrema (the singularform of extrema is extremum), of the function on the interval. In the given problem, the extremum occurs-4when x =3The specified function is f(x) = -3XVX + 2 = -3x(x + 2)/2.Differentiate f(x) using the product rule.+ (x + 2)/2 . (f '(x) = -3x(x + 2)

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Description: Please answer Tutorial ExerciseFind the value of the derivative (if it exists) at the indicated extremum.(금)-4 4V6f(x) = - 3xVx + 210아-4-24-5- 10Step 1The minimum and maximum of a function on an interval are the extreme values, or extrema (the singul

To find: The value of the derivative fx=-3xx+2. Formula used: Product rule of differentiation:…

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Find the value of the derivative (if it exists) at the indicated extremum. -4 4/6 3 f(x) = - 3xVx + 2 10 5 -4 -2 4 -5 – 10- 2.

College Algebra (MindTap Course List)

12th Edition

ISBN:9781305652231

Author:R. David Gustafson, Jeff Hughes

Publisher:R. David Gustafson, Jeff Hughes

Chapter3: Functions

Section3.3: More On Functions; Piecewise-defined Functions

Problem 84E

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Tutorial Exercise
Find the value of the derivative (if it exists) at the indicated extremum.
(금)
-4 4V6
f(x) = - 3xVx + 2
10아
-4
-2
4
-5
- 10
Step 1
The minimum and maximum of a function on an interval are the extreme values, or extrema (the singular
form of extrema is extremum), of the function on the interval. In the given problem, the extremum occurs
-4
when x =
3
The specified function is f(x) = -3XVX + 2 = -3x(x + 2)/2.
Differentiate f(x) using the product rule.
+ (x + 2)/2 . (
f '(x) = -3x
(x + 2)

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