Find the value of integral (+3 (x + y + z)ds, where C is parameterized by ŕ(t) = (4√√2 cos(2t), 9 sin(2t), 7 cos(2t)) for 0 ≤t≤”.

By expanding (xh)2+(yk)2=r2, we obtain x22hx+h22ky+k2r2=0. When we compare this result to the form x2+y2+Dx+Ey+F=0, we see that D=2h,E=2k, and F=h2+k2r2. Therefore, the center and the length of a radius of a circle can be found by using h=D2,k=E2 and r=h2+k2F. Use these relationship to find the center and the length of the radius of each of the following circles. x2+y2+4x14y+49=0

Find dZ for the function : a x 3z x2 sin ( y³ ) + x e³² cos ( z? ) = 3 y - 6 z + 8 .A dz 2 x sin (3y ) + 3e3z -6 - 3x e3z – 2 z sin (2z ) dx .B a z 6 - 3 x e3z - 2 z sin ( z² ) a x 2х cos ( y ) 3z e .C 2 x sin (y3) + e3z 6 — Зхез2 dz %3D dx 2 z sin (z2) .D Зу?x?сos (у3) -з -6 - 3x e3z - 2 z sin (z?) dz Əx |