Find the value of each variable. If your answer is not an integer, round to the nearest tenth. 11. 140 60 of

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**Title: Solving for Unknown Variables in Geometric Diagrams**

**Objective:**
Find the value of each variable. If your answer is not an integer, round to the nearest tenth.

**Problem Statement:**
11.

**Diagram Explanation:**
The diagram shows a circle and a triangle with angles at two intersecting lines.
- There is a circle with a central angle of 60 degrees.
- A straight line intersecting the circle, creating an external angle of 140 degrees.
- A triangle is formed outside the circle, with one of its angles labeled as \( x^\circ \).
- The external angle (140 degrees) and part of the triangle share a straight line segment.


**Solution Explanation:**

1. **Understanding the External Angle:**
   - The external angle given is 140 degrees.
   - The sum of the internal angles on a straight line is 180 degrees.
   - Therefore, the internal adjacent angle to the 140-degree angle is:
     \[
     180^\circ - 140^\circ = 40^\circ
     \]

2. **Using the Central Angle:**
   - The central angle inside the circle (opposite to the segment extending outward) is 60 degrees.
   
3. **Finding the Value of \( x \):**
   - In the triangle formed, the internal angle adjacent to the 140-degree angle is found to be 40 degrees (as calculated).
   - Let’s use the triangle sum property, which states that the sum of angles in a triangle is always 180 degrees.
   - Since one angle is part of a right-angled section within the circle (60 degrees):
     \[
     x + 60^\circ + 40^\circ = 180^\circ
     \]
   - Simplifying,
     \[
     x + 100^\circ = 180^\circ
     \]
   - Solving for \( x \):
     \[
     x = 180^\circ - 100^\circ = 80^\circ
     \]

Therefore, the value of the variable \( x \) is \( 80^\circ \).

**Note:** This problem requires knowledge of the properties of angles in a triangle and the angle sum property. The key concept used is that the sum of the angles in any triangle is always 180 degrees.
Transcribed Image Text:**Title: Solving for Unknown Variables in Geometric Diagrams** **Objective:** Find the value of each variable. If your answer is not an integer, round to the nearest tenth. **Problem Statement:** 11. **Diagram Explanation:** The diagram shows a circle and a triangle with angles at two intersecting lines. - There is a circle with a central angle of 60 degrees. - A straight line intersecting the circle, creating an external angle of 140 degrees. - A triangle is formed outside the circle, with one of its angles labeled as \( x^\circ \). - The external angle (140 degrees) and part of the triangle share a straight line segment. **Solution Explanation:** 1. **Understanding the External Angle:** - The external angle given is 140 degrees. - The sum of the internal angles on a straight line is 180 degrees. - Therefore, the internal adjacent angle to the 140-degree angle is: \[ 180^\circ - 140^\circ = 40^\circ \] 2. **Using the Central Angle:** - The central angle inside the circle (opposite to the segment extending outward) is 60 degrees. 3. **Finding the Value of \( x \):** - In the triangle formed, the internal angle adjacent to the 140-degree angle is found to be 40 degrees (as calculated). - Let’s use the triangle sum property, which states that the sum of angles in a triangle is always 180 degrees. - Since one angle is part of a right-angled section within the circle (60 degrees): \[ x + 60^\circ + 40^\circ = 180^\circ \] - Simplifying, \[ x + 100^\circ = 180^\circ \] - Solving for \( x \): \[ x = 180^\circ - 100^\circ = 80^\circ \] Therefore, the value of the variable \( x \) is \( 80^\circ \). **Note:** This problem requires knowledge of the properties of angles in a triangle and the angle sum property. The key concept used is that the sum of the angles in any triangle is always 180 degrees.
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