Find the value of a and b in the figure below. NGE (2b +9)° (3b) (b – 15)° K (4a) Solving for b: + 2b+9 + b-15 = b. = 180 b%3D Solving for ZNKI ZNKI = b - 15 ZNKI = Solving for a: 4a + = 180 4a = 180 - 4a =

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Find the value of a and b in the figure below.
GE
(2b +9)°
(3b)
(b – 15)° K
(4a)°
Solving for b:
+ 2b+9 + b-15 =
b.
= 180
b% D
Solving for
ZNKI
ZNKI = b - 15
%3D
ZNKI =
Solving for a:
4a +
- 180
4а 3 180-
!!
4a =
Transcribed Image Text:Find the value of a and b in the figure below. GE (2b +9)° (3b) (b – 15)° K (4a)° Solving for b: + 2b+9 + b-15 = b. = 180 b% D Solving for ZNKI ZNKI = b - 15 %3D ZNKI = Solving for a: 4a + - 180 4а 3 180- !! 4a =
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