Find the unique anti-derivative F of 2e5x – 2e²x + 4e−3x e2x f(x) for which F(0) 1. F(x) 2. F(x) 3. F(x) 4. F(x) 5. F(x) 6. F(x) = = = = = = = 2 5 2|3 2|3 213 2|3 3 25 = = 0. 5x 3x 3x 3x 3x 5x - 2x | 2x I + 2x + - 2x T + 2x + + 2x + 4 i10 5 GTP 5⁰ 4 5 2 3 4 5 2 3 -5x -5x -5x - 3x -3x - 3x T GN IN GIN T + 15 22 15 ON EN | 15

Q: Then A-1 If A = 5 1 -16 -3 0 0 0 -1 0 w 00+ 4 -13

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Q: 9

A: As we know that (-1)^2 = 1 (ab)^2= a^2b^2

Q: | (1– 2r)dr

A: Given:∫01(1-2x)dx = ∫011dx- ∫012xdx                     ∫fx±gxdx=∫fxdx±∫gxdx…

Q: 5 25 1+2+20+20+ 4 16 64 an = ||

A: Since you have asked multiple question, we will solve the first question for you as per our guide…

Q: |P(A)| (please think carefully before doing this) A={3,8,11,14,21

A: ANS ;. |P(A)|  A={3,8,11,14,21}

Q: 81. What is wrong with the following calculation? 0 =0 +0 + 0 + ... = (1 – 1) + (1 – 1) + (1 – 1) +…

A: Given a calculation.

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Q: What is the alternative hypothesis? A HaiH> 80 ОВ. На:Х> Haix> 80 O. HaiH<80 O D. Haix < 80 O E.…

A: Solution-: We find the alternative hypothesis

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Q: Find P(AorB) if P(A)=0.3, P(B)=0.5 and A and B are independent

A: P(A) = 0.3 P(B) = 0.5

Q: :) you are awesome

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Q: -(-a) =_____ .

A:

Q: If ?(?∩?)=0.18, and ?(?|?)=0.3, then  ?(?)=

A: Given that  P(A∩B)=0.18, and P(A|B)=0.3, We want to find  P(B)= ?