Find the trigonometric Fourier series for the function f(x): [-π/2, π/2] → R given by the expression: f(x) = ²/2/² FS(x) = FS(x)= FS(x) sinh a 75 = O FS(z) =sinh7|1+2% (-1) (cos 2n +nsin 2ng) ] e)]. sinh a 71 2 sin T T [12 + Σn=1 n²+1 (-1)" (cos 2nx √2+ (-1)" + Σn=1 n²+1 (-1)" sin 2nx) +Σn=1 n+1 (cos 2nx - n sin 2nx) (cos 2nx -n sin 2nx) 2nx)].
Find the trigonometric Fourier series for the function f(x): [-π/2, π/2] → R given by the expression: f(x) = ²/2/² FS(x) = FS(x)= FS(x) sinh a 75 = O FS(z) =sinh7|1+2% (-1) (cos 2n +nsin 2ng) ] e)]. sinh a 71 2 sin T T [12 + Σn=1 n²+1 (-1)" (cos 2nx √2+ (-1)" + Σn=1 n²+1 (-1)" sin 2nx) +Σn=1 n+1 (cos 2nx - n sin 2nx) (cos 2nx -n sin 2nx) 2nx)].
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![Find the trigonometric Fourier series for the function f(x): [-π/2, π/2] → R given by the
expression:
f(x) = ²2
FS(x)
FS(x) =
sinh n
π
FS(x) =
FS(x)=sinh 7|1+2
2
sinh n
T
(-1)^
+ Σn=1 n²+1
(-1)"
inh 71 2n=1 n²+1
sin T
π
1 + ΣΩ
+
-(cos 2nx
(-1)"
n=1 n²+1
+ ΣΩ
sin 2nx)
-(cos 2nx + n sin 2nx)
(cos 2nx n sin 2nx
(-1)" (cos 2nx
n+1
>]
-n sin 2nx)
2nx)].](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F12c62ea9-2423-4a35-a6cd-74646c6bbd41%2Fbe36b0f2-bf18-48b5-89bd-dd42cb0f11ba%2Ftxottb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Find the trigonometric Fourier series for the function f(x): [-π/2, π/2] → R given by the
expression:
f(x) = ²2
FS(x)
FS(x) =
sinh n
π
FS(x) =
FS(x)=sinh 7|1+2
2
sinh n
T
(-1)^
+ Σn=1 n²+1
(-1)"
inh 71 2n=1 n²+1
sin T
π
1 + ΣΩ
+
-(cos 2nx
(-1)"
n=1 n²+1
+ ΣΩ
sin 2nx)
-(cos 2nx + n sin 2nx)
(cos 2nx n sin 2nx
(-1)" (cos 2nx
n+1
>]
-n sin 2nx)
2nx)].
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