Find the transforn 53 9) y= 5cos0+
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![**Problem 9:**
Find the transformations required to obtain the graph starting with a basic trig function.
\( y = 5\cos\left(\theta + \frac{5\pi}{6}\right) \)
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**Explanation:**
The function presented is \( y = 5\cos\left(\theta + \frac{5\pi}{6}\right) \), which is a transformed cosine function from the basic form \( y = \cos(\theta) \).
To understand the transformations involved:
1. **Amplitude Change**: The coefficient of 5 in front of the cosine function indicates a vertical stretch by a factor of 5. This means the amplitude of the cosine wave changes from 1 to 5.
2. **Phase Shift**: The term \(\theta + \frac{5\pi}{6}\) inside the cosine function represents a horizontal shift or phase shift. The graph shifts to the left by \(\frac{5\pi}{6}\) units.
Overall, the basic cosine graph is vertically stretched and shifted left to create this new function.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fabe9e786-be4a-454e-b2cf-16d08b96c793%2F37ce0995-7cb9-4450-af62-813e1d6b607b%2Fh1zhp9e_processed.jpeg&w=3840&q=75)
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