Find the total Coulomb force on a charge of 2.00 nC located at x = 4.00 cm in Figure 18.52(b), given that q = 1.00 μC . (а) x (cm) -29 10 +q +g (b) + + + x (cm) -9 10 -29 +9 +3q Figure 18.52(b) Point charges located at 1.00, 5.00, 8.00, and 14.0 cm along the x-axis. Choose the two correct forces below. 0.252 N to the left 0.252 N to the right -0.252 N to the left

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Chapter16: Electrical Energy And Capacitance
Section: Chapter Questions
Problem 19P: A proton is located at the origin, and a second proton is located on the x-axis at x = 6.00 fm (1 fm...
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### Problem Statement:
Find the total Coulomb force on a charge of 2.00 nC located at \( x = 4.00 \) cm in **Figure 18.52(b)**, given that \( q = 1.00 \, \mu \text{C} \).

### Figure 18.52(b) Explanation:

#### Diagram Description:
- **Figure 18.52(b)** shows two lines marked with point charges positioned along the x-axis at various coordinates:
  - **Line (a)**:
    - At \( x = 0 \, \text{cm} \): +q
    - At \( x = 5 \, \text{cm} \): -2q
    - At \( x = 10 \, \text{cm} \): +q

  - **Line (b)**:
    - At \( x = 0 \, \text{cm} \): -2q
    - At \( x = 5 \, \text{cm} \): +q
    - At \( x = 10 \, \text{cm} \): +3q
    - At \( x = 14 \, \text{cm} \): -q

### Instruction:
Choose the two correct forces below:

#### Answer Choices:
1. \(\square\) \( 0.252 \, \text{N} \) to the left
2. \(\square\) \( 0.252 \, \text{N} \) to the right
3. \(\square\) \( -0.252 \, \text{N} \) to the left
4. \(\square\) \( -0.252 \, \text{N} \) to the right

_Note that the sign and direction of the forces should correspond to the specific point charges and their positions relative to the charge at \( x = 4.00 \, \text{cm} \)._
Transcribed Image Text:### Problem Statement: Find the total Coulomb force on a charge of 2.00 nC located at \( x = 4.00 \) cm in **Figure 18.52(b)**, given that \( q = 1.00 \, \mu \text{C} \). ### Figure 18.52(b) Explanation: #### Diagram Description: - **Figure 18.52(b)** shows two lines marked with point charges positioned along the x-axis at various coordinates: - **Line (a)**: - At \( x = 0 \, \text{cm} \): +q - At \( x = 5 \, \text{cm} \): -2q - At \( x = 10 \, \text{cm} \): +q - **Line (b)**: - At \( x = 0 \, \text{cm} \): -2q - At \( x = 5 \, \text{cm} \): +q - At \( x = 10 \, \text{cm} \): +3q - At \( x = 14 \, \text{cm} \): -q ### Instruction: Choose the two correct forces below: #### Answer Choices: 1. \(\square\) \( 0.252 \, \text{N} \) to the left 2. \(\square\) \( 0.252 \, \text{N} \) to the right 3. \(\square\) \( -0.252 \, \text{N} \) to the left 4. \(\square\) \( -0.252 \, \text{N} \) to the right _Note that the sign and direction of the forces should correspond to the specific point charges and their positions relative to the charge at \( x = 4.00 \, \text{cm} \)._
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