Find the total charge (in C) contained on a disk defined by 2 Ps= Pso. Sin (p) a:=2.cm mC 3 m³ Pso=de.10¹¹.cm-² r≤a

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Find the total charge (in C) contained on a disk defined by
2
Ps= Pso* sin()
a:=2.cm
●
mC
3
m³
11
Pso= 9.10¹¹.cm
-2
ra
Z:=0
Transcribed Image Text:Find the total charge (in C) contained on a disk defined by 2 Ps= Pso* sin() a:=2.cm ● mC 3 m³ 11 Pso= 9.10¹¹.cm -2 ra Z:=0
Expert Solution
Step 1: step 1

The surface charge density of the disk is given by

ρs=ρ0sin2(ϕ)mC/m3

the radius of the disk = 2 cm

The area of the disc = A=π(2102)2=.00125m2

rho subscript 0 equals 1.6 asterisk times 10 to the power of negative 19 end exponent asterisk times 10 to the power of 11 asterisk times 10 to the power of 4 equals space 1.6 asterisk times 10 to the power of negative 4 end exponent space m to the power of negative 2 end exponent

Thus total charge contained in the disc

Q=A02πρsdϕ=A02πρ0sin2(ϕ)

Solving the integration

Q=A02πρ0sin2(ϕ)=Aρ0π C




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