Find the total area of the following rectangle: 20 160 Use the total area found above and the red area found below to determine the missing green area: 20 19
Find the total area of the following rectangle: 20 160 Use the total area found above and the red area found below to determine the missing green area: 20 19
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
![**Educational Content: Calculating Area**
---
**Objective**: Learn how to find the total area of a rectangle and solve for missing areas using subtraction of known areas.
---
**Problem Statement**:
1. **Find the Total Area of the Rectangle**:
- **Dimensions**: The rectangle has a length of 20 units and a height of 8 units.
- The area can be calculated using the formula:
\[
\text{Area} = \text{Length} \times \text{Height}
\]
- **Area Calculation**:
\[
\text{Area} = 20 \times 8 = 160 \text{ square units}
\]
2. **Determine the Missing Green Area**:
- **Diagram Breakdown**:
- The full rectangle from above is 20 units by 8 units.
- Below, the rectangle is divided into two parts: a large part (green) and a smaller red section on the right.
- The red section has a length of 1 unit, making the green section's length 19 units.
- **Given**:
- The total area of the upper rectangle (160 square units).
- The smaller rectangle and red area need to be analyzed to find the missing green area.
- **Red & Entire Rectangle Measurements**:
- The red section's height is the same as the rectangle's height: 8 units.
- Missing length for the red area is 1 unit.
- **Calculate Red Area**:
\[
\text{Red Area} = \text{Height} \times \text{Length} = 8 \times 1 = 8 \text{ square units}
\]
- **To find the green area**:
- Subtract the red area from the total area of the rectangle:
\[
\text{Green Area} = 160 - 8 = 152 \text{ square units}
\]
**Conclusion**: By using the properties of arithmetic and subtraction of areas, you can solve for unknown quantities in geometric shapes.
---
Practice additional problems to master these concepts and calculations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff7d076e1-4d53-497a-8a49-28a21970e8bb%2Fe3062eee-865f-45bc-bf9b-1de8ad054cbd%2Fz351okh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Educational Content: Calculating Area**
---
**Objective**: Learn how to find the total area of a rectangle and solve for missing areas using subtraction of known areas.
---
**Problem Statement**:
1. **Find the Total Area of the Rectangle**:
- **Dimensions**: The rectangle has a length of 20 units and a height of 8 units.
- The area can be calculated using the formula:
\[
\text{Area} = \text{Length} \times \text{Height}
\]
- **Area Calculation**:
\[
\text{Area} = 20 \times 8 = 160 \text{ square units}
\]
2. **Determine the Missing Green Area**:
- **Diagram Breakdown**:
- The full rectangle from above is 20 units by 8 units.
- Below, the rectangle is divided into two parts: a large part (green) and a smaller red section on the right.
- The red section has a length of 1 unit, making the green section's length 19 units.
- **Given**:
- The total area of the upper rectangle (160 square units).
- The smaller rectangle and red area need to be analyzed to find the missing green area.
- **Red & Entire Rectangle Measurements**:
- The red section's height is the same as the rectangle's height: 8 units.
- Missing length for the red area is 1 unit.
- **Calculate Red Area**:
\[
\text{Red Area} = \text{Height} \times \text{Length} = 8 \times 1 = 8 \text{ square units}
\]
- **To find the green area**:
- Subtract the red area from the total area of the rectangle:
\[
\text{Green Area} = 160 - 8 = 152 \text{ square units}
\]
**Conclusion**: By using the properties of arithmetic and subtraction of areas, you can solve for unknown quantities in geometric shapes.
---
Practice additional problems to master these concepts and calculations.
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