Find the time it takes for $5,000 to double when invested at an annual interest rate of 6%, compounded continuously. years Find the time it takes for $500,000 to double when invested at an annual interest rate of 6%, compounded continuously. years Give your answers accurate to 4 decimal places. Question Help: Video
Find the time it takes for $5,000 to double when invested at an annual interest rate of 6%, compounded continuously. years Find the time it takes for $500,000 to double when invested at an annual interest rate of 6%, compounded continuously. years Give your answers accurate to 4 decimal places. Question Help: Video
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.3: The Natural Exponential Function
Problem 40E
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Question
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### Doubling Time Calculation for Continuous Compounding
#### Problem Statement:
1. **Find the time it takes for $5,000 to double when invested at an annual interest rate of 6%, compounded continuously.**
- __________ years
2. **Find the time it takes for $500,000 to double when invested at an annual interest rate of 6%, compounded continuously.**
- __________ years
#### Instructions:
- **Give your answers accurate to 4 decimal places.**
To solve these problems, we can use the formula for continuous compounding:
\[ A = P e^{rt} \]
Where:
- \( A \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount (the initial amount of money).
- \( r \) is the annual interest rate (decimal).
- \( t \) is the time the money is invested for, in years.
- \( e \) is the base of the natural logarithm (approximately equal to 2.71828).
For the amount to double, \( A = 2P \). The equation becomes:
\[ 2P = P e^{rt} \]
Dividing both sides by \( P \):
\[ 2 = e^{rt} \]
Taking the natural logarithm of both sides:
\[ \ln(2) = rt \]
Solving for \( t \):
\[ t = \frac{\ln(2)}{r} \]
Given the annual interest rate \( r \) is 6% or 0.06, we can substitute into the formula to find the time \( t \) for each problem.
For further assistance, please watch the instructional video by clicking the video link.
**Submit your answer by clicking the “Submit Question” button below.**
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Transcribed Image Text:---
### Doubling Time Calculation for Continuous Compounding
#### Problem Statement:
1. **Find the time it takes for $5,000 to double when invested at an annual interest rate of 6%, compounded continuously.**
- __________ years
2. **Find the time it takes for $500,000 to double when invested at an annual interest rate of 6%, compounded continuously.**
- __________ years
#### Instructions:
- **Give your answers accurate to 4 decimal places.**
To solve these problems, we can use the formula for continuous compounding:
\[ A = P e^{rt} \]
Where:
- \( A \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount (the initial amount of money).
- \( r \) is the annual interest rate (decimal).
- \( t \) is the time the money is invested for, in years.
- \( e \) is the base of the natural logarithm (approximately equal to 2.71828).
For the amount to double, \( A = 2P \). The equation becomes:
\[ 2P = P e^{rt} \]
Dividing both sides by \( P \):
\[ 2 = e^{rt} \]
Taking the natural logarithm of both sides:
\[ \ln(2) = rt \]
Solving for \( t \):
\[ t = \frac{\ln(2)}{r} \]
Given the annual interest rate \( r \) is 6% or 0.06, we can substitute into the formula to find the time \( t \) for each problem.
For further assistance, please watch the instructional video by clicking the video link.
**Submit your answer by clicking the “Submit Question” button below.**
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[Submit Question]
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