Find the time it takes for $5,000 to double when invested at an annual interest rate of 6%, compounded continuously. years Find the time it takes for $500,000 to double when invested at an annual interest rate of 6%, compounded continuously. years Give your answers accurate to 4 decimal places. Question Help: Video

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.3: The Natural Exponential Function
Problem 40E
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### Doubling Time Calculation for Continuous Compounding

#### Problem Statement:

1. **Find the time it takes for $5,000 to double when invested at an annual interest rate of 6%, compounded continuously.**
   - __________ years

2. **Find the time it takes for $500,000 to double when invested at an annual interest rate of 6%, compounded continuously.**
   - __________ years

#### Instructions:
- **Give your answers accurate to 4 decimal places.**

To solve these problems, we can use the formula for continuous compounding:

\[ A = P e^{rt} \]

Where:
- \( A \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount (the initial amount of money).
- \( r \) is the annual interest rate (decimal).
- \( t \) is the time the money is invested for, in years.
- \( e \) is the base of the natural logarithm (approximately equal to 2.71828).

For the amount to double, \( A = 2P \). The equation becomes:

\[ 2P = P e^{rt} \]

Dividing both sides by \( P \):

\[ 2 = e^{rt} \]

Taking the natural logarithm of both sides:

\[ \ln(2) = rt \]

Solving for \( t \):

\[ t = \frac{\ln(2)}{r} \]

Given the annual interest rate \( r \) is 6% or 0.06, we can substitute into the formula to find the time \( t \) for each problem.

For further assistance, please watch the instructional video by clicking the video link.

**Submit your answer by clicking the “Submit Question” button below.**

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[Submit Question]

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Transcribed Image Text:--- ### Doubling Time Calculation for Continuous Compounding #### Problem Statement: 1. **Find the time it takes for $5,000 to double when invested at an annual interest rate of 6%, compounded continuously.** - __________ years 2. **Find the time it takes for $500,000 to double when invested at an annual interest rate of 6%, compounded continuously.** - __________ years #### Instructions: - **Give your answers accurate to 4 decimal places.** To solve these problems, we can use the formula for continuous compounding: \[ A = P e^{rt} \] Where: - \( A \) is the amount of money accumulated after n years, including interest. - \( P \) is the principal amount (the initial amount of money). - \( r \) is the annual interest rate (decimal). - \( t \) is the time the money is invested for, in years. - \( e \) is the base of the natural logarithm (approximately equal to 2.71828). For the amount to double, \( A = 2P \). The equation becomes: \[ 2P = P e^{rt} \] Dividing both sides by \( P \): \[ 2 = e^{rt} \] Taking the natural logarithm of both sides: \[ \ln(2) = rt \] Solving for \( t \): \[ t = \frac{\ln(2)}{r} \] Given the annual interest rate \( r \) is 6% or 0.06, we can substitute into the formula to find the time \( t \) for each problem. For further assistance, please watch the instructional video by clicking the video link. **Submit your answer by clicking the “Submit Question” button below.** --- [Submit Question] ---
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