Find the time complexity of following iterative algorithm. a) void Test1 (int n) { int count = 0; for (int i=n/2; i<=n; i++) for (int j=1; j<=n; j = 2 * j) for (int k=1; k<=n; k = k * 2) count++; }

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A: Answer. Time Complexity = O(n^2) Space Complexity = O(1)

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A: According to the Question below the Solution:

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A: Hello student Hope you are learning well.

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A: summary: - hence we discussed all the points

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A: Required:

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