Find the Thévenin equivalent circuit for the portion of the network of Fig. 19.119 external to the elements between points a and b. R E = 100 V Z 0° | XL Xc FIG. 19.119

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**Problem Statement:**

Find the Thévenin equivalent circuit for the portion of the network of Fig. 19.119 external to the elements between points a and b.

**Diagram Explanation (Fig. 19.119):**

- The circuit features an AC voltage source labeled \( E = 100 \, V \, \angle 0^\circ \).
- A resistor \( R \) with a resistance of \( 3 \, \Omega \) is connected in series.
- A parallel branch consists of two components:
  - An inductor \( X_L \) with an inductive reactance of \( 4 \, \Omega \).
  - A capacitor \( X_C \) with a capacitive reactance of \( 2 \, \Omega \).
- The points \( a \) and \( b \) are marked at the ends of the parallel branch (induction and capacitance).

This diagram illustrates a complex impedance network with components in both series and parallel configurations, necessitating the calculation of the Thévenin equivalent to simplify analysis between points \( a \) and \( b \).
Transcribed Image Text:**Problem Statement:** Find the Thévenin equivalent circuit for the portion of the network of Fig. 19.119 external to the elements between points a and b. **Diagram Explanation (Fig. 19.119):** - The circuit features an AC voltage source labeled \( E = 100 \, V \, \angle 0^\circ \). - A resistor \( R \) with a resistance of \( 3 \, \Omega \) is connected in series. - A parallel branch consists of two components: - An inductor \( X_L \) with an inductive reactance of \( 4 \, \Omega \). - A capacitor \( X_C \) with a capacitive reactance of \( 2 \, \Omega \). - The points \( a \) and \( b \) are marked at the ends of the parallel branch (induction and capacitance). This diagram illustrates a complex impedance network with components in both series and parallel configurations, necessitating the calculation of the Thévenin equivalent to simplify analysis between points \( a \) and \( b \).
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