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Find the Thevenin and Norton equivalent circuit at terminals a-b for the circuit shown below, where R= 10 2. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. 25/30° V j20 2 m ZN=Zth= 22.36 Vth = IN = 25 ( 1.11 ( (a) R wwwo a --j10 22 -150 °) V °) A ob ) Ω

Find the Thevenin and Norton equivalent circuit at terminals a-b for the circuit shown below, where R= 10 2. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. 25/30° V j20 2 m ZN=Zth= 22.36 Vth = IN = 25 ( 1.11 ( (a) R wwwo a --j10 22 -150 °) V °) A ob ) Ω

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Find the Thevenin and Norton equivalent circuit at terminals a-b for the circuit shown below, where R = 10 2. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. 25/30° V ZN = Zth Vth IN = j20 2 m (a) 22.36 Z 25 ( 1.11 ( R www o a -j10 22 -150 °) V °) A -o b Ω
Transcribed Image Text:Find the Thevenin and Norton equivalent circuit at terminals a-b for the circuit shown below, where R = 10 2. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. 25/30° V ZN = Zth Vth IN = j20 2 m (a) 22.36 Z 25 ( 1.11 ( R www o a -j10 22 -150 °) V °) A -o b Ω
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