How do you find the z score and p value? Suon HeipInvestigators performed a randomized experiment in which 420 juvenile delinquents were randomly assigned to either multisystemic therapy (MST) or just probation(control group). Of the 219 assigned to therapy, 88 had criminal convictions within 12 months. Of the 201 in the control group, 74 had criminal convictions within 12months. Determine whether the therapy caused significantly fewer arrests at a 0.01 significance level. Start by comparing the sample percentages.The percentage of arrests for people who received probation was 36.82 %.(Type an integer or decimal rounded to two decimal places as needed.)The arrest rate was greater for people in the treatment group.Let p, represent the population proportion for people who are arrested after having received the treatment and let p2 represent the population proportion of peoplewho are arrested after having not received the treatment. Write the hypotheses for the test.Ho: P1= P2Ha: P1

Given: Level of significance = 0.01 Let, therapy - G1 control group - G2 p(G1)= p1 = 88/219 =…

Answered: Find the test statistic for this test.…

Find the test statistic for this test. (Round to two decimal places as needed.) Find the p-value for this test. p-value = (Round to three decimal places as needed.)

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN:9780547587776

Author:HOLT MCDOUGAL

Publisher:HOLT MCDOUGAL

Chapter11: Data Analysis And Probability

Section11.4: Collecting Data

Problem 3E

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Concept explainers

Confidence Intervals

When we calculate intervals in probability and statistics, it can be simply termed as finding out a confidence interval. The confidence interval is usually calculated from the data set which is observed. The value of the parameter that needs to be calculated is present here only.

Question

How do you find the z score and p value?

Suon Heip
Investigators performed a randomized experiment in which 420 juvenile delinquents were randomly assigned to either multisystemic therapy (MST) or just probation
(control group). Of the 219 assigned to therapy, 88 had criminal convictions within 12 months. Of the 201 in the control group, 74 had criminal convictions within 12
months. Determine whether the therapy caused significantly fewer arrests at a 0.01 significance level. Start by comparing the sample percentages.
The percentage of arrests for people who received probation was 36.82 %.
(Type an integer or decimal rounded to two decimal places as needed.)
The arrest rate was greater for people in the treatment group.
Let p, represent the population proportion for people who are arrested after having received the treatment and let p2 represent the population proportion of people
who are arrested after having not received the treatment. Write the hypotheses for the test.
Ho: P1= P2
Ha: P1<P2
Find the test statistic for this test.
z=
(Round to two decimal places as needed.)
Find the p-value for this test.
p-value =
(Round to three decimal places as needed.)

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