Find the temperature of a person in percentile-99, given that we expect the average temperature tobe 98.6 with a standard deviation of 0.7. Round your answer to one decimal place.percentile 9996.5 97.2 97.9 98.6 99.3temp100100.7 101.temperature=Hint: Try using StatKey. or a spreadsheet, =NORMINV(p, mean, std)

given data normal distributionμ = 98.6σ = 0.7find 99th percentile = ?

Answered: Find the temperature of a person in…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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instructor gives a 100-point examination in which the grades are normally distributed. The mean is 66 and the standard deviation is 5. If there are 5% A's and 5% F's, 15% B's and 15% D's, and 60% C's, find the scores that divide the distribution into those categories. Round the cutoff scores to the nearest whole number. Round intermediate z-value calculations to 2 decimal places. A:_- B: C: D: --- F: _-_
Jse the Empirical Rule. The mean speed of a sample of vehicles along a stretch of highway is 64 miles per hour, with a standard deviation of 4 miles per hour. Estimate the percent of vehicles whose speeds are between miles per hour and 72 miles per hour. (Assume the data set has a bell-shaped distribution.) Approximately % of vehicles travel between 56 miles per hour and 72 miles per hour.
Hi Please help. Thank you. Total cholesterol in children aged 10 to 15 years of age is assume to follow a normal distribution with a mean of 191 and a standard deviation of 22.4. What is the 90 percentile of total cholesterol?
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Cereals sodium values have a mean of 167 and a standard deviation of 77.3. Find the z-score for the cereal that has a sodium value of 0. How would you interpret this z-score?
The coefficient of variation CV describes the standard deviation as a percent of the mean. Because it has no units, you can use the coefficient of variation to compare data with different units. Find the coefficient of variation for each sample data set. What can you conclude? Standard deviation CV = • 100% Mean E Click the icon to view the data sets. Data Table C/heights = 5.0 % (Round to the nearest tenth as needed.) Heights Weights CVweights =% (Round to the nearest tenth as needed.) 68 181 77 169 72 167 72 207 71 177 70 175 78 185 69 186 67 221 70 216 67 209 73 206
The IRS claims it takes an average of 3.7 hours to complete a 1040 tax form. Assume the time t the form is normally distributed with a standard deviation of 15 minutes or 0.25 hours. complete Use the Cumulative Z-Score Table to answer the following questions. Write your answer as a percent using 2 decimal places. What percent of people would you expect to complete the form in less than 3.45 hours? What percent of people would you expect to complete the form-in more than 3.45 hours? What percent of people would you expect to complete the form in less than 3.4 hours? What percent of people would you expect to complete the form in more than 3.4 hours? What percent of people would you expect to complete the form between 3.4 and 3.45 hours?
Dataset Available: Download Houston.xlsx You may need to use the appropriate appendix table or technology to answer this question. Data were collected on the amount spent by 64 customers for lunch at a major Houston restaurant. These data are contained in the file Houston. Based upon past studies the population standard deviation is known with a = $6. 20.50 14.63 23.77 29.96 28.87 15.78 18.16. 12.16 18.89 19.88 23.11 20.11 20.34 27.49 36.55 21.18 19.22 34.13 25.53 27.71 33.81 21.79 29.49 32.70 9.20 20.89 11.22 16.43 17.66 9.59 Need Help? Read It 19.16 26.35 20.01 26.85 13.63 17.22 13.17 20.12 22.11 22.47 20.36 35.47 11.85 17.88 6.83 30.99 18.38 26.85 25.10 20.08 30.36 21.79 14.62 Watch It 18.37 32.27 12.63 27.55 25.87 14.37 15.61 26.46 24.24 16.66 20.85 (a) At 99% confidence, what is the margin of error in dollars? (Round your answer to the nearest cent.) $ (b) Develop a 99% confidence interval estimate of the mean amount spent for lunch in dollars. (Round your answers to the nearest…
Find the mean and standard deviation for the individualized instruction s cores. Scores Individualized Instruction 50 - 59 60 - 69 70 - 79 6 80 - 89 11 90 – 99 6. Mean = (Round to the nearest hundredth.) Standard deviation =| (Round to the nearest hundredth.)

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