Find the Taylor series for f(x) centered at the given value of a. f (2) = x* – 5x2 +1, a = 2 f(n) (2) (г — 2)" — 3-12 (r — 2)+19 (т — 2)? +8 (г — 2)8 + (г — 2)" n! O n=0 f(m) (2) (r – 2)" = 3+12 (x – 2)+19 (x – 2)² –8 (x – 2)* +(x – 2)4 - n! O n=0 f(m) (2) (x – 2)" = -3+12 (x – 2)+8 (x – 2)²+19(x – 2)³+(x – 2)4 n! O n=0 f(m) (2) (r – 2)" = -3+12 (x – 2)+19 (r – 2)²+8(r – 2)°+(x – 2)* n! O n=0 f(m) (2) (г — 2)" — — 3+12 (г — 2)—8 (т — 2)2+19 (т — 2)8— (х — 2)4 n! n=0 Need Help? Read It 8W! W! W! W! W!

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