Find the Taylor polynomial of order 3 generated by f at a. 1 a = 1 x + 10' 31) f(x) = 1 A) P3(x) = 9 x + 1 (x + 1)2 (x + 1)3 1 B) P3(x) = 11 x + 1 (x + 1)2 (x + 1)3 81 729 6561 121 1331 14,641 1 (х - 1)2 (х- 1)3 1 D) P3(x) = 11 x - 1, (x - 1)2 (x - 1)3 (x - 1)2 (x - 1)³ X - C) P3(x) =- 9 81 729 6561 121 1331 14,641

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 4E
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**Find the Taylor polynomial of order 3 generated by f at a.**

Given: 
\[ f(x) = \frac{1}{x+10} \]
\[ a = 1 \]

Choose the correct expression for \( P_3(x) \):

A) 
\[ P_3(x) = \frac{1}{9} - \frac{x + 1}{81} + \frac{(x + 1)^2}{729} - \frac{(x + 1)^3}{6561} \]

B)
\[ P_3(x) = \frac{1}{11} - \frac{x + 1}{121} + \frac{(x + 1)^2}{1331} - \frac{(x + 1)^3}{14,641} \]

C)
\[ P_3(x) = \frac{1}{9} - \frac{x - 1}{81} + \frac{(x - 1)^2}{729} - \frac{(x - 1)^3}{6561} \]

D)
\[ P_3(x) = \frac{1}{11} - \frac{x - 1}{121} + \frac{(x - 1)^2}{1331} - \frac{(x - 1)^3}{14,641} \]
Transcribed Image Text:**Find the Taylor polynomial of order 3 generated by f at a.** Given: \[ f(x) = \frac{1}{x+10} \] \[ a = 1 \] Choose the correct expression for \( P_3(x) \): A) \[ P_3(x) = \frac{1}{9} - \frac{x + 1}{81} + \frac{(x + 1)^2}{729} - \frac{(x + 1)^3}{6561} \] B) \[ P_3(x) = \frac{1}{11} - \frac{x + 1}{121} + \frac{(x + 1)^2}{1331} - \frac{(x + 1)^3}{14,641} \] C) \[ P_3(x) = \frac{1}{9} - \frac{x - 1}{81} + \frac{(x - 1)^2}{729} - \frac{(x - 1)^3}{6561} \] D) \[ P_3(x) = \frac{1}{11} - \frac{x - 1}{121} + \frac{(x - 1)^2}{1331} - \frac{(x - 1)^3}{14,641} \]
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