→ Find the Taylor polynomial centered at a = 0 for each function. Use summation notation or expanded notation. f(x) = e(5x)

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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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## Taylor Polynomial Expansion

### Problem Statement:
Find the Taylor polynomial centered at \( a = 0 \) for each function. Use summation notation or expanded notation.

Given function:
\[ f(x) = e^{(5x)} \]

### Detailed Steps:

To determine the Taylor polynomial for \( f(x) = e^{5x} \) centered at \( a = 0 \), we use the Taylor series expansion formula:

\[ f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!} (x - a)^n \]

Since \( a = 0 \), the formula simplifies to:

\[ f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(0)}{n!} x^n \]

The function \( f(x) = e^{5x} \) has the property that its derivatives are:

\[ f^{(n)}(x) = \frac{d^n}{dx^n} e^{5x} = 5^n e^{5x} \]

Evaluating at \( x = 0 \), we get:

\[ f^{(n)}(0) = 5^n \]

Plugging this into the Taylor series formula yields:

\[ f(x) = \sum_{n=0}^{\infty} \frac{5^n}{n!} x^n \]

Or in expanded form:

\[ f(x) = 1 + 5x + \frac{(5x)^2}{2!} + \frac{(5x)^3}{3!} + \frac{(5x)^4}{4!} + \cdots \]

In summary, the Taylor polynomial for \( f(x) = e^{5x} \) centered at \( a = 0 \) is:

\[ f(x) = \sum_{n=0}^{\infty} \frac{5^n}{n!} x^n \]
Transcribed Image Text:## Taylor Polynomial Expansion ### Problem Statement: Find the Taylor polynomial centered at \( a = 0 \) for each function. Use summation notation or expanded notation. Given function: \[ f(x) = e^{(5x)} \] ### Detailed Steps: To determine the Taylor polynomial for \( f(x) = e^{5x} \) centered at \( a = 0 \), we use the Taylor series expansion formula: \[ f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!} (x - a)^n \] Since \( a = 0 \), the formula simplifies to: \[ f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(0)}{n!} x^n \] The function \( f(x) = e^{5x} \) has the property that its derivatives are: \[ f^{(n)}(x) = \frac{d^n}{dx^n} e^{5x} = 5^n e^{5x} \] Evaluating at \( x = 0 \), we get: \[ f^{(n)}(0) = 5^n \] Plugging this into the Taylor series formula yields: \[ f(x) = \sum_{n=0}^{\infty} \frac{5^n}{n!} x^n \] Or in expanded form: \[ f(x) = 1 + 5x + \frac{(5x)^2}{2!} + \frac{(5x)^3}{3!} + \frac{(5x)^4}{4!} + \cdots \] In summary, the Taylor polynomial for \( f(x) = e^{5x} \) centered at \( a = 0 \) is: \[ f(x) = \sum_{n=0}^{\infty} \frac{5^n}{n!} x^n \]
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