Find the surface area of the cube shown below.

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Question

Find the surface area of the cube shown below. 

### Calculating the Surface Area of a Cube

#### Problem Statement:
Find the surface area of the cube shown below.

#### Input box for answer:
`__________ units^2`

#### Diagram:
A cube is shown with dimensions clearly marked. The side length of the cube is given as \( \frac{2}{3} \) units.

---

**Explanation:**

To find the surface area of a cube, you can use the following formula:

\[ \text{Surface Area} = 6 \times \text{side length}^2 \]

For the given cube:

- Side length (\( s \)) = \( \frac{2}{3} \) units

Plugging in the side length value:

\[ \text{Surface Area} = 6 \times \left( \frac{2}{3} \right)^2 \]

First, square the side length:

\[ \left( \frac{2}{3} \right)^2 = \frac{4}{9} \]

Then, multiply by 6:

\[ \text{Surface Area} = 6 \times \frac{4}{9} = \frac{24}{9} = \frac{8}{3} \]

Thus, the surface area of the cube is:

\[ \frac{8}{3} \text{ units}^2 \]
Transcribed Image Text:### Calculating the Surface Area of a Cube #### Problem Statement: Find the surface area of the cube shown below. #### Input box for answer: `__________ units^2` #### Diagram: A cube is shown with dimensions clearly marked. The side length of the cube is given as \( \frac{2}{3} \) units. --- **Explanation:** To find the surface area of a cube, you can use the following formula: \[ \text{Surface Area} = 6 \times \text{side length}^2 \] For the given cube: - Side length (\( s \)) = \( \frac{2}{3} \) units Plugging in the side length value: \[ \text{Surface Area} = 6 \times \left( \frac{2}{3} \right)^2 \] First, square the side length: \[ \left( \frac{2}{3} \right)^2 = \frac{4}{9} \] Then, multiply by 6: \[ \text{Surface Area} = 6 \times \frac{4}{9} = \frac{24}{9} = \frac{8}{3} \] Thus, the surface area of the cube is: \[ \frac{8}{3} \text{ units}^2 \]
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