Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question
Find the surface area of the cube shown below.
![### Calculating the Surface Area of a Cube
#### Problem Statement:
Find the surface area of the cube shown below.
#### Input box for answer:
`__________ units^2`
#### Diagram:
A cube is shown with dimensions clearly marked. The side length of the cube is given as \( \frac{2}{3} \) units.
---
**Explanation:**
To find the surface area of a cube, you can use the following formula:
\[ \text{Surface Area} = 6 \times \text{side length}^2 \]
For the given cube:
- Side length (\( s \)) = \( \frac{2}{3} \) units
Plugging in the side length value:
\[ \text{Surface Area} = 6 \times \left( \frac{2}{3} \right)^2 \]
First, square the side length:
\[ \left( \frac{2}{3} \right)^2 = \frac{4}{9} \]
Then, multiply by 6:
\[ \text{Surface Area} = 6 \times \frac{4}{9} = \frac{24}{9} = \frac{8}{3} \]
Thus, the surface area of the cube is:
\[ \frac{8}{3} \text{ units}^2 \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdc19db7c-4792-4fd2-b3d8-699ca1486fb3%2F4292ee11-6e7a-4d3d-9f53-1912541fc60c%2F2mfwnmd_reoriented.jpeg&w=3840&q=75)
Transcribed Image Text:### Calculating the Surface Area of a Cube
#### Problem Statement:
Find the surface area of the cube shown below.
#### Input box for answer:
`__________ units^2`
#### Diagram:
A cube is shown with dimensions clearly marked. The side length of the cube is given as \( \frac{2}{3} \) units.
---
**Explanation:**
To find the surface area of a cube, you can use the following formula:
\[ \text{Surface Area} = 6 \times \text{side length}^2 \]
For the given cube:
- Side length (\( s \)) = \( \frac{2}{3} \) units
Plugging in the side length value:
\[ \text{Surface Area} = 6 \times \left( \frac{2}{3} \right)^2 \]
First, square the side length:
\[ \left( \frac{2}{3} \right)^2 = \frac{4}{9} \]
Then, multiply by 6:
\[ \text{Surface Area} = 6 \times \frac{4}{9} = \frac{24}{9} = \frac{8}{3} \]
Thus, the surface area of the cube is:
\[ \frac{8}{3} \text{ units}^2 \]
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