Find the surface area of a square-based pyramid whose lateral faces are isosceles triangles with base length 10 inches and lateral height 8 inches. A 100 inches? ® 160 inches² 260 inches? D 420 inches?

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
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ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter10: Measurement, Area, And Volume
Section: Chapter Questions
Problem 19CR
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Find the surface area of a square-based pyramid whose lateral faces are isoceles triangles with base lenght 10 inches and lateral height 8 inches.

Find the surface area of a square-based pyramid whose
lateral faces are isosceles triangles with base length
10 inches and lateral height 8 inches.
A 100 inches²
B.
® 160 inches²
260 inches?
D
420 inches?
Transcribed Image Text:Find the surface area of a square-based pyramid whose lateral faces are isosceles triangles with base length 10 inches and lateral height 8 inches. A 100 inches² B. ® 160 inches² 260 inches? D 420 inches?
Expert Solution
Step 1
  • Pyramid has four lateral faces and one base face. Total surface area = base area + 4 lateral face area.
  • Base area is a square with side A1 = a2 units.
  • Lateral faces are isoscale triangles A2 = 4(area of isoscale triangles).
  • Area of isoscale triangle = (1/2)*side*lateral height  (lateral for pyramid)

                 A2 = 4*(1/2)*a*l = 2al

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