Find the surface area of a square-based pyramid whose lateral faces are isosceles triangles with base length 10 inches and lateral height 8 inches. A 100 inches? ® 160 inches² 260 inches? D 420 inches?
Find the surface area of a square-based pyramid whose lateral faces are isosceles triangles with base length 10 inches and lateral height 8 inches. A 100 inches? ® 160 inches² 260 inches? D 420 inches?
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter10: Measurement, Area, And Volume
Section: Chapter Questions
Problem 19CR
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Question
Find the surface area of a square-based pyramid whose lateral faces are isoceles triangles with base lenght 10 inches and lateral height 8 inches.
![Find the surface area of a square-based pyramid whose
lateral faces are isosceles triangles with base length
10 inches and lateral height 8 inches.
A 100 inches²
B.
® 160 inches²
260 inches?
D
420 inches?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F631aa397-f06f-4605-8e1b-f2fcfe75648b%2Ff694afe6-df03-4311-baac-3076c724a4c1%2Fmzwgb2e_processed.png&w=3840&q=75)
Transcribed Image Text:Find the surface area of a square-based pyramid whose
lateral faces are isosceles triangles with base length
10 inches and lateral height 8 inches.
A 100 inches²
B.
® 160 inches²
260 inches?
D
420 inches?
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
- Pyramid has four lateral faces and one base face. Total surface area = base area + 4 lateral face area.
- Base area is a square with side A1 = a2 units.
- Lateral faces are isoscale triangles A2 = 4(area of isoscale triangles).
- Area of isoscale triangle = (1/2)*side*lateral height (lateral for pyramid)
A2 = 4*(1/2)*a*l = 2al
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