Find the surface area for the portion of the surface f(x,y)=1-x² + y that lies above the triangular region in the xy plane with vertices (1,0), (0,-1), and (0,1) as illustrated below. Surface: fix,y)=1-x²+y (0.1.2)

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Find the surface area for the portion of the surface f(x,y) = 1-x² + y that lies above the
triangular region in the xy plane with vertices (1,0), (0,-1), and (0,1) as illustrated below.
Surface:
f(x, y)=1-x² + y
(0.1.2)
Transcribed Image Text:Find the surface area for the portion of the surface f(x,y) = 1-x² + y that lies above the triangular region in the xy plane with vertices (1,0), (0,-1), and (0,1) as illustrated below. Surface: f(x, y)=1-x² + y (0.1.2)
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