Find the sum. 6 E k2 k = 1

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem:** Find the sum.

\( \sum_{k=1}^{6} k^2 \)

**Explanation:**

The given expression is a sigma notation that represents the sum of the squares of the first 6 positive integers. The notation can be broken down as follows:

- The lower limit of the summation is \(k = 1\), which means the summation starts from \(k = 1\).
- The upper limit of the summation is 6, which means the sum will be calculated up to \(k = 6\).
- The term being summed is \(k^2\), which means you will square each integer from 1 to 6 and then add them together.
  So, the sum can be written out in expanded form as:
  \[
  1^2 + 2^2 + 3^2 + 4^2 + 5^2 + 6^2
  \]
  To calculate the sum:
  \[
  1 + 4 + 9 + 16 + 25 + 36
  \]
  \[
  = 91
  \]

Place your final answer in the provided input box.

**Interactive Element:**
- Input Box: Enter your answer (the sum of the squares) in the provided box to check your solution.
Transcribed Image Text:**Problem:** Find the sum. \( \sum_{k=1}^{6} k^2 \) **Explanation:** The given expression is a sigma notation that represents the sum of the squares of the first 6 positive integers. The notation can be broken down as follows: - The lower limit of the summation is \(k = 1\), which means the summation starts from \(k = 1\). - The upper limit of the summation is 6, which means the sum will be calculated up to \(k = 6\). - The term being summed is \(k^2\), which means you will square each integer from 1 to 6 and then add them together. So, the sum can be written out in expanded form as: \[ 1^2 + 2^2 + 3^2 + 4^2 + 5^2 + 6^2 \] To calculate the sum: \[ 1 + 4 + 9 + 16 + 25 + 36 \] \[ = 91 \] Place your final answer in the provided input box. **Interactive Element:** - Input Box: Enter your answer (the sum of the squares) in the provided box to check your solution.
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