Find the sum. 37+38+39+40+...103+104

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Find the sum.

37+38+39+40+...103+104

### Summation Problem

#### Problem Statement:
Find the sum \( 37 + 38 + 39 + 40 + \ldots + 103 + 104 \).

#### Answer Box:
The sum is \[ \_\_\_\_\_\}.
  
#### Instructions:
Enter your answer in the answer box and then click "Check Answer".

---

#### Explanation:
In this problem, we are asked to find the sum of a sequence of consecutive integers starting from 37 and ending at 104.

To solve this, we can use the formula for the sum of an arithmetic series:
\[ \text{Sum} = \frac{n}{2} \times (\text{first term} + \text{last term}) \]

where \( n \) is the number of terms in the series.

1. **First Term (a):** 37
2. **Last Term (l):** 104
3. **Number of Terms (n):**

\[ n = \text{last term} - \text{first term} + 1 \]
\[ n = 104 - 37 + 1 = 68 \]

4. **Sum Calculation:**
\[ \text{Sum} = \frac{n}{2} \times (a + l) \]
\[ \text{Sum} = \frac{68}{2} \times (37 + 104) \]
\[ \text{Sum} = 34 \times 141 \]
\[ \text{Sum} = 4794 \]

Thus, the sum of the series from 37 to 104 is **4794**.
Transcribed Image Text:### Summation Problem #### Problem Statement: Find the sum \( 37 + 38 + 39 + 40 + \ldots + 103 + 104 \). #### Answer Box: The sum is \[ \_\_\_\_\_\}. #### Instructions: Enter your answer in the answer box and then click "Check Answer". --- #### Explanation: In this problem, we are asked to find the sum of a sequence of consecutive integers starting from 37 and ending at 104. To solve this, we can use the formula for the sum of an arithmetic series: \[ \text{Sum} = \frac{n}{2} \times (\text{first term} + \text{last term}) \] where \( n \) is the number of terms in the series. 1. **First Term (a):** 37 2. **Last Term (l):** 104 3. **Number of Terms (n):** \[ n = \text{last term} - \text{first term} + 1 \] \[ n = 104 - 37 + 1 = 68 \] 4. **Sum Calculation:** \[ \text{Sum} = \frac{n}{2} \times (a + l) \] \[ \text{Sum} = \frac{68}{2} \times (37 + 104) \] \[ \text{Sum} = 34 \times 141 \] \[ \text{Sum} = 4794 \] Thus, the sum of the series from 37 to 104 is **4794**.
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