Find the sum of the values of f(x) = x³ over the integers 1, 2, 3, ..., 10.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement**

Find the sum of the values of \( f(x) = x^3 \) over the integers \( 1, 2, 3, \ldots, 10 \).

**Solution**

To solve this problem, we need to calculate the sum of the cubes of the integers from 1 to 10. Specifically, we need to find:

\[
f(1) + f(2) + f(3) + \cdots + f(10)
\]

Given the function \( f(x) = x^3 \), substitute \( x \) with integers from 1 to 10 and sum them up:

\[
1^3 + 2^3 + 3^3 + \cdots + 10^3
\]

First, we calculate each cube:

\[
\begin{align*}
1^3 & = 1 \\
2^3 & = 8 \\
3^3 & = 27 \\
4^3 & = 64 \\
5^3 & = 125 \\
6^3 & = 216 \\
7^3 & = 343 \\
8^3 & = 512 \\
9^3 & = 729 \\
10^3 & = 1000 \\
\end{align*}
\]

Next, sum these values:

\[
1 + 8 + 27 + 64 + 125 + 216 + 343 + 512 + 729 + 1000
\]

\[
= 3025
\]

So, the sum of the values of \( f(x) = x^3 \) over the integers from 1 to 10 is \( 3025 \).

Therefore, the answer is:

\[
\boxed{3025}
\]
Transcribed Image Text:**Problem Statement** Find the sum of the values of \( f(x) = x^3 \) over the integers \( 1, 2, 3, \ldots, 10 \). **Solution** To solve this problem, we need to calculate the sum of the cubes of the integers from 1 to 10. Specifically, we need to find: \[ f(1) + f(2) + f(3) + \cdots + f(10) \] Given the function \( f(x) = x^3 \), substitute \( x \) with integers from 1 to 10 and sum them up: \[ 1^3 + 2^3 + 3^3 + \cdots + 10^3 \] First, we calculate each cube: \[ \begin{align*} 1^3 & = 1 \\ 2^3 & = 8 \\ 3^3 & = 27 \\ 4^3 & = 64 \\ 5^3 & = 125 \\ 6^3 & = 216 \\ 7^3 & = 343 \\ 8^3 & = 512 \\ 9^3 & = 729 \\ 10^3 & = 1000 \\ \end{align*} \] Next, sum these values: \[ 1 + 8 + 27 + 64 + 125 + 216 + 343 + 512 + 729 + 1000 \] \[ = 3025 \] So, the sum of the values of \( f(x) = x^3 \) over the integers from 1 to 10 is \( 3025 \). Therefore, the answer is: \[ \boxed{3025} \]
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