Find the sum of the series. 71=0 312-4 5+1

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Find the sum of the series:

\[
\sum_{n=0}^{\infty} \frac{3^{n+2} - 4^n}{5^{n+1}}
\]

**Explanation:**

This mathematical expression represents an infinite series where each term is described by the formula:

\[
\frac{3^{n+2} - 4^n}{5^{n+1}}
\]

- **Series Definition:**
  - **Summation Index (n):** The index \( n \) starts at 0 and goes to infinity.
  - **Numerator:** The expression \( 3^{n+2} - 4^n \) involves powers of 3 and 4.
  - **Denominator:** The power of 5 in the denominator is \( 5^{n+1} \).

The task is to calculate the sum of all terms in this infinite series.
Transcribed Image Text:**Problem Statement:** Find the sum of the series: \[ \sum_{n=0}^{\infty} \frac{3^{n+2} - 4^n}{5^{n+1}} \] **Explanation:** This mathematical expression represents an infinite series where each term is described by the formula: \[ \frac{3^{n+2} - 4^n}{5^{n+1}} \] - **Series Definition:** - **Summation Index (n):** The index \( n \) starts at 0 and goes to infinity. - **Numerator:** The expression \( 3^{n+2} - 4^n \) involves powers of 3 and 4. - **Denominator:** The power of 5 in the denominator is \( 5^{n+1} \). The task is to calculate the sum of all terms in this infinite series.
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