find the sum of the moments of the Forces in kN.m about Point O, (positive in the counter- clockwise direction). F1 = 60 kN and F2 = 22 kN.
find the sum of the moments of the Forces in kN.m about Point O, (positive in the counter- clockwise direction). F1 = 60 kN and F2 = 22 kN.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
![**Problem Statement:**
Find the sum of the moments of the forces in kN·m about Point O, with counter-clockwise direction being positive.
Given:
- F1 = 60 kN
- F2 = 22 kN
**Diagram Explanation:**
The diagram shows a horizontal and vertical force system with a right angle.
- There is a 9-meter vertical segment from the base to the horizontal line.
- A horizontal segment, labeled as 15 meters long, extends to the right from the top of the vertical line, ending at Point O.
- F1 (60 kN) is acting horizontally to the right at the junction of the horizontal and vertical segments.
- F2 (22 kN) is acting vertically upward at the base of the vertical segment.
**Steps for Calculation:**
1. Calculate the moment due to F1: \( \text{Moment}_{F1} = F1 \times \text{Distance} = 60 \text{ kN} \times 9 \text{ m} \)
2. Calculate the moment due to F2: \( \text{Moment}_{F2} = F2 \times \text{Distance} = 22 \text{ kN} \times 15 \text{ m} \)
Combine the moments, remembering to consider the direction (counter-clockwise is positive).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8dc0b9fd-45c2-41df-86dc-3db8d4d245ae%2Fdd5312f2-d541-44ad-af13-92f05b107ba0%2Fi43fd4k_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Find the sum of the moments of the forces in kN·m about Point O, with counter-clockwise direction being positive.
Given:
- F1 = 60 kN
- F2 = 22 kN
**Diagram Explanation:**
The diagram shows a horizontal and vertical force system with a right angle.
- There is a 9-meter vertical segment from the base to the horizontal line.
- A horizontal segment, labeled as 15 meters long, extends to the right from the top of the vertical line, ending at Point O.
- F1 (60 kN) is acting horizontally to the right at the junction of the horizontal and vertical segments.
- F2 (22 kN) is acting vertically upward at the base of the vertical segment.
**Steps for Calculation:**
1. Calculate the moment due to F1: \( \text{Moment}_{F1} = F1 \times \text{Distance} = 60 \text{ kN} \times 9 \text{ m} \)
2. Calculate the moment due to F2: \( \text{Moment}_{F2} = F2 \times \text{Distance} = 22 \text{ kN} \times 15 \text{ m} \)
Combine the moments, remembering to consider the direction (counter-clockwise is positive).
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Moment is defined as the product of the Force and the perpendicular distance from the line of action of the force to the point about which moment is to be determined.
Moment can be understood as a turning effect of a force about a point or axis.
In the given system the perpendicular distance between the forces, F1 and F2 from point O has been shown by l1 and l2. The below given figure clearly shows the distances and the conventions of Moments
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