Chapter12: Sequences, Series And Binomial Theorem
Section: Chapter Questions
Problem 327PT: Find the twenty-third term of an arithmetic sequence whose seventh term is 11 and common difference...
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![**Arithmetic Sequences on Educational Platform**
---
### Problem Statement:
**Find the sum of the indicated number of terms of the arithmetic sequence.**
**Sequence:** 34, 29, 24, ...
**Number of terms:** \( n = 21 \)
---
**Solution:**
To solve this problem, let's use the formula for the sum of the first \( n \) terms of an arithmetic sequence:
\[ S_n = \frac{n}{2} (2a + (n-1)d) \]
Where:
- \( S_n \) is the sum of the first \( n \) terms.
- \( n \) is the number of terms.
- \( a \) is the first term.
- \( d \) is the common difference between the terms.
Given:
- \( a = 34 \)
- \( d = 29 - 34 = -5 \)
- \( n = 21 \)
Now let's substitute these values into the formula:
\[ S_{21} = \frac{21}{2} [2(34) + (21 - 1)(-5)] \]
\[ S_{21} = \frac{21}{2} [68 + 20(-5)] \]
\[ S_{21} = \frac{21}{2} [68 - 100] \]
\[ S_{21} = \frac{21}{2} [-32] \]
\[ S_{21} = 21 \times -16 \]
\[ S_{21} = -336 \]
So, the sum of the first 21 terms of the arithmetic sequence is **-336**.
### Graphical Representation:
The provided image does not include any graphs or diagrams, and hence, no graphical representation accompanies this problem on the educational platform.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F667c2432-c02d-4ad1-9d8f-1347249c5b46%2Fdae630a1-457f-4791-a046-c0d850d07845%2Fly0q55u.jpeg&w=3840&q=75)
Transcribed Image Text:**Arithmetic Sequences on Educational Platform**
---
### Problem Statement:
**Find the sum of the indicated number of terms of the arithmetic sequence.**
**Sequence:** 34, 29, 24, ...
**Number of terms:** \( n = 21 \)
---
**Solution:**
To solve this problem, let's use the formula for the sum of the first \( n \) terms of an arithmetic sequence:
\[ S_n = \frac{n}{2} (2a + (n-1)d) \]
Where:
- \( S_n \) is the sum of the first \( n \) terms.
- \( n \) is the number of terms.
- \( a \) is the first term.
- \( d \) is the common difference between the terms.
Given:
- \( a = 34 \)
- \( d = 29 - 34 = -5 \)
- \( n = 21 \)
Now let's substitute these values into the formula:
\[ S_{21} = \frac{21}{2} [2(34) + (21 - 1)(-5)] \]
\[ S_{21} = \frac{21}{2} [68 + 20(-5)] \]
\[ S_{21} = \frac{21}{2} [68 - 100] \]
\[ S_{21} = \frac{21}{2} [-32] \]
\[ S_{21} = 21 \times -16 \]
\[ S_{21} = -336 \]
So, the sum of the first 21 terms of the arithmetic sequence is **-336**.
### Graphical Representation:
The provided image does not include any graphs or diagrams, and hence, no graphical representation accompanies this problem on the educational platform.
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