Find the sum of the first 10 terms of the following series, to the nearest integer. 10, 40, 160, ...

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Problem Statement:**
Find the sum of the first 10 terms of the following series, to the nearest integer.

**Given Series:**
10, 40, 160, ...

---

To solve this, we need to identify the type of series and then apply the appropriate formula. The given series 10, 40, 160, ... is a geometric sequence because each term after the first is obtained by multiplying the previous term by a constant ratio.

**Step-by-Step Solution:**

1. **Identify the First Term (a):**
    - The first term \( a \) is 10.

2. **Calculate the Common Ratio (r):**
    - The common ratio \( r \) is obtained by dividing the second term by the first term, or the third term by the second term.
    - \( r = \frac{40}{10} = 4 \)
    - This can also be verified by \( r = \frac{160}{40} = 4 \).

3. **Sum of the First n Terms (S_n) of a Geometric Sequence:**
    - The formula for the sum of the first \( n \) terms of a geometric sequence is:
    \[
    S_n = a \frac{r^n - 1}{r - 1}
    \]
    - Substituting the known values into the formula to find the sum of the first 10 terms:
    \[
    S_{10} = 10 \frac{4^{10} - 1}{4 - 1}
    \]

4. **Simplify the Expression:**
    - Calculate \( 4^{10} \):
    \[
    4^{10} = 1048576
    \]
    - Substitute \( 1048576 \) into the sum formula:
    \[
    S_{10} = 10 \frac{1048576 - 1}{3} = 10 \frac{1048575}{3} = 10 \cdot 349525 = 3495250
    \]

5. **Round to the Nearest Integer:**
    - The sum of the first 10 terms rounded to the nearest integer is \( \boxed{3495250} \).

---

**Conclusion:**
The sum of the first 10 terms of the given geometric series 10, 40, 160, ... is approximately 3,
Transcribed Image Text:**Problem Statement:** Find the sum of the first 10 terms of the following series, to the nearest integer. **Given Series:** 10, 40, 160, ... --- To solve this, we need to identify the type of series and then apply the appropriate formula. The given series 10, 40, 160, ... is a geometric sequence because each term after the first is obtained by multiplying the previous term by a constant ratio. **Step-by-Step Solution:** 1. **Identify the First Term (a):** - The first term \( a \) is 10. 2. **Calculate the Common Ratio (r):** - The common ratio \( r \) is obtained by dividing the second term by the first term, or the third term by the second term. - \( r = \frac{40}{10} = 4 \) - This can also be verified by \( r = \frac{160}{40} = 4 \). 3. **Sum of the First n Terms (S_n) of a Geometric Sequence:** - The formula for the sum of the first \( n \) terms of a geometric sequence is: \[ S_n = a \frac{r^n - 1}{r - 1} \] - Substituting the known values into the formula to find the sum of the first 10 terms: \[ S_{10} = 10 \frac{4^{10} - 1}{4 - 1} \] 4. **Simplify the Expression:** - Calculate \( 4^{10} \): \[ 4^{10} = 1048576 \] - Substitute \( 1048576 \) into the sum formula: \[ S_{10} = 10 \frac{1048576 - 1}{3} = 10 \frac{1048575}{3} = 10 \cdot 349525 = 3495250 \] 5. **Round to the Nearest Integer:** - The sum of the first 10 terms rounded to the nearest integer is \( \boxed{3495250} \). --- **Conclusion:** The sum of the first 10 terms of the given geometric series 10, 40, 160, ... is approximately 3,
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