Find the standard deviation
Q: Claim: The standard deviation of pulse rates of adult males is less than 10 bpm. For a random…
A: Given Pulse rate of adult male is less than 10
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Q: Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69.1 bpm. For a random…
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Q: Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69.1 bpm. For a random…
A: Claims in statistic is tested using the hypothesis testing. In the hypothesis test of mean, the null…
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Q: Claim: The standard deviation of pulse rates of adult males is more than 10 bpm. For a random sample…
A: The given claim is that the standard deviation of pulse rates of adult males is more than 10 bpm.
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Q: Assume that females have pulse rates that are normally distributed with a mean of μ=74.0 beats per…
A: Given information- Population mean, μ = 74.0 beats Population standard deviation, σ = 12.5 beats per…
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Q: Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69.2 bpm. For a random…
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Q: The mean pulse rate (in beats per minute) of adult males is equa rd deviation is 10.9 bpm. Complete…
A: The claim is that the mean pulse rate is equal to 69.1
Q: K Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69.1 bpm. For a random…
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Q: Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69.1 bpm. For a random…
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Q: ciaim The standard deviation of pulse rates of adult males is less than 11 tom For a rando sample of…
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Q: laim: The standard deviation of pulse rates of adult males is more than 1 1.9 bpm. Complete parts…
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Q: Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random…
A: Given Claim : The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm.…
Q: 0 1 2 3 Xj РX - х) 0.20 0.30 0.40 0.10 What is the standard deviation of X? 0.840 0.090 1.345 0.917
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Q: Claim: The standard deviation of pulse rates of adult males is less than 11 bpm. For a random sample…
A: Solution: From the given information, the claim is that the standard deviation of pulse rates of…
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Q: b) Calculate the sample standard deviation c) Using the p value approach at the 1% level of…
A: Given: ∑x=205∑x-x¯2=56.43n=50α=0.01Thus,x¯=20550=4.1 Part b: The sample standard deviation is…
Q: Claim: The standard deviation of pulse rates of adult males is less than 10 bpm. For a random sample…
A: According to the provided information, claim: the standard deviation of pulse rates of adult males…
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Find the standard deviation. Si f 3 3 5 7 7 5
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We have to calculate the standard deviation for the given frequency distribution
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- Claim: The standard deviation of pulse rates of adult males is less than 11 bpm. For a random sample of 173 adult males, the pulse rates have a standard deviation of 10.8 bpm. Complete parts (a) and (b) below. a. Express the original claim in symbolic form. 7 V bpm (Type an integer or a decimal. Do not round.)O pis posIbi A population has a mean u=78 and a standard deviation o = 26. Find the mean and standard deviation of a sampling distribution of sample means with sample size n= 264. H; =(Simplify your answer.) o: =(Type an integer or decimal rounded to three decimal places as needed.) Enter your answer in each of the answer boxes. 20K The IQ scores for a random sample of subjects with low lead levels in their blood and another random sample of subjects with high lead levels in their blood were collected. The statistics are summarized in the accompanying table. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Complete parts (a) to (c) below. tcrunch @ W S OA. Ho: H₁ H2 H₁: H1 H2 = OC. Ho: P1 P2 H₁: H1 H₂ The test statistic is a. Use a 0.05 significance level to test the claim that the mean IQ score of people with low blood lead levels is higher than the mean IQ score of people with high blood lead levels. What are the null and alternative hypotheses? Assume that population 1 consists of subjects with low lead levels and population 2 consists of subjects with high lead levels. The P-value is State the conclusion for the test. Tech help ZO F3 (Round to two decimal places as needed.) (Round…
- A popular theory is that presidential candidates have an advantage if they are taller than their main opponents. Listed are heights (in centimeters) of randomly selected presidents along with the heights of their main opponents. Complete parts (a) and (b) below. Height (cm) of President 185 170 179 191 194 179 9 Height (cm) of Main Opponent 170 184 174 166 194 182 Identify the test statistic. t= 0.57 (Round to two decimal places as needed.) Identify the P-value P-value = 0.286 (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? Since the P-value is greater than the significance level, fail to reject the null hypothesis. There is not sufficient evidence to support the claim that presidents tend to be taller than their opponents. b. Construct the confidence interval that could be used for the hypothesis test described in part (a). What feature of the confidence interval leads to the same conclusion reached in part (a)? The confidence interval…A study of seat belt users and nonusers yielded the randomly selected sample data summarized in the accompanying table. Use a 0.05 significance level to test the claim that the amount of smoking is independent of seat belt use. A plausible theory is that people who smoke are less concerned about their health and safety and are therefore less inclined to wear seat belts. Is this theory supported by the sample data? E Click the icon to view the data table. Determine the test statistic. *= (Round to three decimal places as needed.) Determine the P-value of the test statistic. P-Value (Round to three decimal places as needed.) Use a 0.05 significance level to test the claim that the amount of smoking is independent of seat belt use. A plausible theory is that people who smoke are less concerned about their health and safety and are therefore less inclined to wear seat belts. Is this theory supported by the sample data?1.3 In a recent survey, 10,000 households were randomly selected. One of the questions on the survey asked how many TVs they had. The results are given in the table below. Number of TVs to number of households # of TVs # of Households P(X=x) 0 160 1 3140 2 3790 3 1920 4 780 5 210 Total 10,000 e) What is the average number of TVs in a household?
- How many students took the test?Find the margin of error for the given values of c, α, and n. c=0.90, α=3.9, n=100K Assume that females have pulse rates that are normally distributed with a mean of μ = 76.0 beats per minute and a standard deviation of o= 12.5 beats per minute. Complete parts (a) through (c) below. a. If 1 adult female is randomly selected, find the probability that her pulse rate is less than 79 beats per minute. The probability is (Round to four decimal places as needed.) b. If 16 adult females are randomly selected, find the probability that they have pulse rates with a mean less than 79 beats per minute. The probability is (Round to four decimal places as needed.) c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30? OA. Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size. OB. Since the distribution is of individuals, not sample means, the distribution is a normal distribution for any sample size. OC. Since the distribution is of sample means, not…
- 3) During a study, the weights of test subjects was recorded. The results are displayed in the graph below. Use the graph to determine the value of the following descriptive statistics Histogram of Wt (n=40) 20 15 10 10 100 150 X Values D How many weights were recorded? D) What is the average weight? O Approximate the standard deviation. d) What is the one-standard deviation interval around the mean? How many weights were within this interval? I What percentage of weights were within this interval? What is the two standard deviation interval around the mean? hi How many weights werE within this interval? What percentage of we were within thisterva What is the three standard deviation ntervalarund the mean K) How many weights were within this interv What percentage of weights were withiin thikinterval? 梦 $ hpK Assume that females have pulse rates that are normally distributed with a mean of μ = 76.0 beats per minute and a standard deviation of o= 12.5 beats per minute. Complete parts (a) through (c) below. a. If 1 adult female is randomly selected, find the probability that her pulse rate is less than 82 beats per minute. The probability is (Round to four decimal places as needed.) b. If 4 adult females are randomly selected, find the probability that they have pulse rates with a mean less than 82 beats per minute. The probability is (Round to four decimal places as needed.) c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30? OA. Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size. OB. Since the mean pulse rate exceeds 30, the distribution of sample means is a normal distribution for any sample size. C. Since the distribution is of individuals, not sample…I need help answering 26. (a-e)
