Find the standard deviation of the random variable X with the given probability distribution. * 1 2 3 P(x) 0.34 0.25 0.20
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Q: Five males with an X-linked genetic disorder have one child each. The random variable x is the…
A: Given PMF of X. Now will using this pmf to find required information
Q: Five males with an X-linked genetic disorder have one child each. The random variable x is the…
A: From the provided information, The probability distribution table can be constructed as: X 0…
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Q: Five males with an X-linked genetic disorder have one child each. The random variable x is the…
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Q: Five males with an X-linked genetic disorder have one child each. The random variable x is the…
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Q: Five males with an X-linked genetic disorder have one child each. The random variable x is the…
A: Mean(μ)=E(X)=∑X.P(X)E(X2)=∑X2.P(X)Variance(σ2)=E(X2)-(E(X))2Standard deviation(σ)=E(X2)-(E(X))2
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- Five males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the X-linked genetic disorder. Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviation. If a probability distribution is not given, identify the requirements that are not satisfied. x P(x) 0 0.028 1 0.152 2 0.320 3 0.320 4 0.152 5 0.028Five males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the X-linked genetic disorder. Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviation. If a probability distribution is not given, identify the requirements that are not satisfied. P(x) 0.032 1 0.161 2 0.307 3 0.307 4 0.161 5 0.032 Does the table show a probability distribution? Select all that apply. A. Yes, the table shows a probability distribution. B. No, the random variable x is categorical instead of numerical. C. No, the random variable x's number values are not associated with probabilities. D. No, not every probability is between 0 and 1 inclusive. E. No, the sum of all the probabilities is not equal to 1.A random variable X follows the uniform distribution with a lower limit of 750 and an upper limit of 800. a. Calculate the mean and the standard deviation for the distribution. (Round intermediate calculation for standard deviation to 4 decimal places and final answer to 2 decimal places.) Mean Standard deviation ces b. What is the probability that X is less than 770? (Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.) Probability Mc Graw Hill Liducation Type here to search 6. (? 653 2/21/20 60 7. 1ock E U home F enter D GO H. K pause C * shift alt ctri
- Five males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the X-linked genetic disorder. Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviation. If a probability distribution is not given, identify the requirements that are not satisfied. P(x) 0.032 1 0.164 2 0.304 0.304 4 0.164 0.032 A. Yes, the table shows a probability distribution. B. No, not every probability is between 0 and 1 inclusive. C. No, the sum of all the probabilities is not equal to 1. D. No, the random variable x's number values are not associated with probabilities. E. No, the random variable x is categorical instead of numerical. Find the mean of the random variable x. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. child(ren) (Round to one decimal place as needed.) B. The table does not show a…X P(x) 0 0.15 1 1 0.25 2 0.2 3 0.4 Find the standard deviation of this probability distribution. Give your answer to at least 2 decimal places Submit Question acerFive males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the X-linked genetic disorder. Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviation. If a probability distribution is not given, identify the requirements that are not satisfied. x P(x) 0 0.027 1 0.145 2 0.328 3 0.328 4 0.145 5 0.027 Question content area bottom Part 1 Does the table show a probability distribution? Select all that apply. A. Yes, the table shows a probability distribution. B. No, the random variable x's number values are not associated with probabilities. C. No, the random variable x is categorical instead of numerical. D. No, the sum of all the probabilities is not equal…
- Compute the mean and standard deviation of the random variable with the given discrete probability distribution. x Px −5 0.11 1 0.26 4 0.23 6 0.28 8 0.12 (a) Find the mean. Round the answer to three decimal places, if necessary. (b) Find the standard deviation. Round the answer to three decimal places, if necessary.Consider the given discrete probability distribution. X 1 2 3 4 P(X=x) 0.07 0.18 0.25 0.5 Find the following probability. Write your answer in two decimal places. P(X>3)=?Five males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the X-linked genetic disorder. Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviation. If a probability distribution is not given, identify the requirements that are not satisfied. x P(x) 0 0.027 1 0.165 2 0.308 3 0.308 4 0.165 5 0.027 Does the table show a probability distribution? Select all that apply. A. Yes, the table shows a probability distribution. B. No, not every probability is between 0 and 1 inclusive. C. No, the random variable x's number values are not associated with probabilities. D. No, the random variable x is categorical instead of numerical. E. No, the sum of all the probabilities is…