Find the speed of an orbiter in a circular orbit that is just above the surface of a planet, given that the orbiter's acceleration is equal to the planet's gravitational acceleration of 2.65 m/s^2. The radius of the planet is 1.41*10^6 m.
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![Find the speed of an orbiter in a circular orbit that is just above the surface of a planet,
given that the orbiter's acceleration is equal to the planet's gravitational acceleration
of 2.65 m/s^2. The radius of the planet is 1.41*10^6 m.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4b4cd5c7-217e-45ce-aa30-2e65bd654f2d%2F1d8666f8-073a-4572-beb3-00709939c21c%2F98kktbe_processed.jpeg&w=3840&q=75)
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