Find the speed of an orbiter in a circular orbit that is just above the surface of a planet, given that the orbiter's acceleration is equal to the planet's gravitational acceleration of 2.65 m/s^2. The radius of the planet is 1.41*10^6 m.

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Find the speed of an orbiter in a circular orbit that is just above the surface of a planet,
given that the orbiter's acceleration is equal to the planet's gravitational acceleration
of 2.65 m/s^2. The radius of the planet is 1.41*10^6 m.
Transcribed Image Text:Find the speed of an orbiter in a circular orbit that is just above the surface of a planet, given that the orbiter's acceleration is equal to the planet's gravitational acceleration of 2.65 m/s^2. The radius of the planet is 1.41*10^6 m.
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