Add the square root steps to the solved problem 3m^3-24m^2-2m+16=0 following the example EXaCTLY Find the solutions for 40r³ - 8r²-25r+ 5 = 0√40-14./102/1058√5√8 √8√40की$440r²³-8√²) + (-25v+5) = 08r² (5r-1) - 5 (5-1) = 0(5r-1)(8r²-5)=05r-1=0+1 +156=1r= 1/s8r²5=0+S +S2-√rer = ± √किtr= + 14088 = ± √io8r² = §²=5${₁+√103Print Find the real number solutions for 3m³ - 24m² - 2m + 16 = 0 using Factoring by Grouping. Show everystep for full credit.(③²-24m²)+(2m+16)=03m²(3-3) - 2cm-8) =0(m-g] (3²-2)=07-8-0+8+8m=8ima-2=0tata3m²=2r/m33ma=23\m² =그리고m=1들

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Find the solutions for 40r³ - 8r²-25r+5=0 √40-14./10 2510 00016000 √40 100 Le $4 (40 r3-8r2)+(-25r+5) = 0 8r² (6r-1)-5(5r-1)=0 (5r-1)(8r²-5) = 0 5r-1=0 +1 +1 5r=1 r= 1/s y 8r²5=0 +S +S 8r² = § -2=5 + r=ts F: + 140 r= t Print

Find the solutions for 40r³ - 8r²-25r+5=0 √40-14./10 2510 00016000 √40 100 Le $4 (40 r3-8r2)+(-25r+5) = 0 8r² (6r-1)-5(5r-1)=0 (5r-1)(8r²-5) = 0 5r-1=0 +1 +1 5r=1 r= 1/s y 8r²5=0 +S +S 8r² = § -2=5 + r=ts F: + 140 r= t Print

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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