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Find the solutions for 40r³ - 8r²-25r+5=0 √40-14./10 2510 00016000 √40 100 Le $4 (40 r3-8r2)+(-25r+5) = 0 8r² (6r-1)-5(5r-1)=0 (5r-1)(8r²-5) = 0 5r-1=0 +1 +1 5r=1 r= 1/s y 8r²5=0 +S +S 8r² = § -2=5 + r=ts F: + 140 r= t Print

Find the solutions for 40r³ - 8r²-25r+5=0 √40-14./10 2510 00016000 √40 100 Le $4 (40 r3-8r2)+(-25r+5) = 0 8r² (6r-1)-5(5r-1)=0 (5r-1)(8r²-5) = 0 5r-1=0 +1 +1 5r=1 r= 1/s y 8r²5=0 +S +S 8r² = § -2=5 + r=ts F: + 140 r= t Print

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Add the square root steps to the solved problem 3m^3-24m^2-2m+16=0 following the example EXaCTLY

Find the solutions for 40r³ - 8r²-25r+ 5 = 0 √40-14./10 2/10 58 √5 √8 √8 √40 की $4 40r²³-8√²) + (-25v+5) = 0 8r² (5r-1) - 5 (5-1) = 0 (5r-1)(8r²-5)=0 5r-1=0 +1 +1 56=1 r= 1/s 8r²5=0 +S +S 2- √re r = ± √ कि t r= + 140 8 8 = ± √io 8r² = § ²=5 ${₁+√103 Print
Transcribed Image Text:Find the solutions for 40r³ - 8r²-25r+ 5 = 0 √40-14./10 2/10 58 √5 √8 √8 √40 की $4 40r²³-8√²) + (-25v+5) = 0 8r² (5r-1) - 5 (5-1) = 0 (5r-1)(8r²-5)=0 5r-1=0 +1 +1 56=1 r= 1/s 8r²5=0 +S +S 2- √re r = ± √ कि t r= + 140 8 8 = ± √io 8r² = § ²=5 ${₁+√103 Print
Find the real number solutions for 3m³ - 24m² - 2m + 16 = 0 using Factoring by Grouping. Show every step for full credit. (③²-24m²)+(2m+16)=0 3m²(3-3) - 2cm-8) =0 (m-g] (3²-2)=0 7-8-0 +8+8 m=8 ima-2=0 tata 3m²=2 r/m 3 3 ma=2 3 \m² = 그리고 m=1 들
Transcribed Image Text:Find the real number solutions for 3m³ - 24m² - 2m + 16 = 0 using Factoring by Grouping. Show every step for full credit. (③²-24m²)+(2m+16)=0 3m²(3-3) - 2cm-8) =0 (m-g] (3²-2)=0 7-8-0 +8+8 m=8 ima-2=0 tata 3m²=2 r/m 3 3 ma=2 3 \m² = 그리고 m=1 들
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