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Find the solutions for 3x² + 1 =(-2x using the quadratic formula. Do we have 1 real number solution, 2 real number solutions or 2 complex. Is everything on the same side and in standard form? No Identify a, b and c. 3x²+2x+1=0 a=3 b=2 c=1 X=-2 ± √(2) ²4 (3) (1) 2 (3) X=-2+1-8 6 -1 as dive %63 and ± i√√₂ 3 -b± √b²-4ac 2a | Can I Simplify √-8? i√8 = 154.5 = 2√2 & => 2 Complex Solutions because my radicand was negative resulting

Find the solutions for 3x² + 1 =(-2x using the quadratic formula. Do we have 1 real number solution, 2 real number solutions or 2 complex. Is everything on the same side and in standard form? No Identify a, b and c. 3x²+2x+1=0 a=3 b=2 c=1 X=-2 ± √(2) ²4 (3) (1) 2 (3) X=-2+1-8 6 -1 as dive %63 and ± i√√₂ 3 -b± √b²-4ac 2a | Can I Simplify √-8? i√8 = 154.5 = 2√2 & => 2 Complex Solutions because my radicand was negative resulting

Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter12: Quadratic Functions
Section: Chapter Questions
Problem 5CR
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A student has solved the problem 6x^2-4x=-7. But he is missing a step. Use the example to add in the step he missed.

Find the solutions for 3x2 + 1 =(-2x using the quadratic formula. Do we have 1 real number solution, 2 real number solutions or 2 complex. Is everything on the same side and in standard form? No Identify a, b and c. X=-2 ± √(2) ²4 (3) (1) 2 (3) X = -2± √-8 6 = 3x²+2x+1=0 X= a = 3 b=2 c = 1 - l SI Dive 2+Q²√₂ (2 ± √₂ | %3 W 3 1 -b± √b²-4ac 2a Can I Simplify! => Simplify √-8? C√8=154.12 = 2√2 $ 2 Complex Solutions because my radicand was Negative resulting
Transcribed Image Text:Find the solutions for 3x2 + 1 =(-2x using the quadratic formula. Do we have 1 real number solution, 2 real number solutions or 2 complex. Is everything on the same side and in standard form? No Identify a, b and c. X=-2 ± √(2) ²4 (3) (1) 2 (3) X = -2± √-8 6 = 3x²+2x+1=0 X= a = 3 b=2 c = 1 - l SI Dive 2+Q²√₂ (2 ± √₂ | %3 W 3 1 -b± √b²-4ac 2a Can I Simplify! => Simplify √-8? C√8=154.12 = 2√2 $ 2 Complex Solutions because my radicand was Negative resulting
Find the solutions for 6x² - 4x = -7 using the Quadratic Formula. S 5x-4x+7=0 a=6₁b = -4₁ <= 7. x = −(²4) ± √√²4)*-4(6) (7) 2(6) X= 4√²-152 12 x=2+i√√39 6. 2 complex roots
Transcribed Image Text:Find the solutions for 6x² - 4x = -7 using the Quadratic Formula. S 5x-4x+7=0 a=6₁b = -4₁ <= 7. x = −(²4) ± √√²4)*-4(6) (7) 2(6) X= 4√²-152 12 x=2+i√√39 6. 2 complex roots
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