Find the solution. (D5 - 2D3 - 2D2- 3D - 2)y = 0. y =c,e+ce+c,e²r+c,cosx + c zsinx y = (c,+c,x)e*+c;e+c,cosx +c gsinx Dy= (c,+cx)e*+c;e-2" +e*(c ,cosx +cgsinx) -3x %3D

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question 4
Find the solution.
(D5 - 2D3 - 2D2- 3D - 2)y = 0.
Ay = c,e+c,e+c;e+c,cosx + c ,sinxr
® y = (e,+c,x)e-+c3
-2x
(c.cosx+c,sinx)
© y = (c,+c,x)e*+c,e+c,cosx +c 35sinx
Dy= (e,+c,x)e+cze-*+e*(¢ ,cosx +e sinx)
-3x
Transcribed Image Text:Question 4 Find the solution. (D5 - 2D3 - 2D2- 3D - 2)y = 0. Ay = c,e+c,e+c;e+c,cosx + c ,sinxr ® y = (e,+c,x)e-+c3 -2x (c.cosx+c,sinx) © y = (c,+c,x)e*+c,e+c,cosx +c 35sinx Dy= (e,+c,x)e+cze-*+e*(¢ ,cosx +e sinx) -3x
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