Question 15Find the solution.(D5 - 2D3 - 2D2- 3D - 2)y = 0.-2xA y = (c,+cx)e¯*+c,e=+e*(c,cosr +C gsinx)® y = (c,+cx)e=«+c;e+e=(c,cosx + € zsinx)-2xy = (c,+c,x)e¯*+cze"+c_cosx+ c sinxDy = c,e*+c,e*+c;e* +c ,cosx +c zsinx

Given differential equation is (D5-2D3-2D2-3D-2)y = 0

Answered: Find the solution. (D5 - 2D3 - 2D2- 3D…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Find the solution. (D5 - 2D3 - 2D2- 3D - 2)y = 0. -3x y = (c,+c,x)e-*+c;e-+e*(c,cosx+c gsinxr) -2x A y = (c,+c,x)e-+ cze *+e=2*(c ,cosx +c ,sinx) B y = (c,+c,t)e*+cze +c,cosx + c gsinx y = c,e* +c,e*+c;e?"+c,cosr + c 3sinx D

Find the solution. (D5 - 2D3 - 2D2- 3D - 2)y = 0. -3x y = (c,+c,x)e-+c;e-+e(c,cosx+c gsinxr) -2x A y = (c,+c,x)e-+ cze +e=2(c ,cosx +c ,sinx) B y = (c,+c,t)e+cze +c,cosx + c gsinx y = c,e +c,e*+c;e?"+c,cosr + c 3sinx D