Find the solution. (D³ –2D2 -5D +6)y =0; when x =0, y=1, y'= -7, y"= -1 A y = -e - e2t y = -e+ 2e -2x (C) y = -e-3*+ 2e2r Dy = e3+2e-2r

i) Find a particular solution by undetermined coefficients. ii) Find a particular solution by variation of parameters. iii) Are the answers the same? If not, what is the difference?

If y=8x3+2x2+5xy=8x3+2x2+5x, then d2y/dx2=