Find the solution vector of the given system by applying Gauss-Seidel method for 2 iterations with the intial vector x0) = (0,0,0)'. 9. -2x1 + x2 +x3 = 4 X2 + 2x3 = 0 1 X1 – 2x2 = -4 A.) x(²) = (-1.0000, 1.0000, –0.5000) B.) x(2) = (1.2500, –1.3333,0.6666)' C.) x(2) = (-1.6250, –5.3750, 2.6875) D.) x(2) = (1.2500, –0.9166,0.0666) E.) x(2) = (-1.6250, 1.3125, –0.6562)

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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9.
Find the solution vector of the given system by applying Gauss-Seidel
method for 2 iterations with the intial vector x0) = (0,0,0)'.
-2x1 + x2 +x3 = 4
X2 + 2x3 = 0
1
X1 – 2x2 -x3 = -4
A.) x(2) = (-1.0000, 1.0000, –0.5000)
В) х(2) — (1.2500, —1.3333,0.6666)*
C.) x2) = (-1.6250, –5.3750, 2.6875)
D.) x(2) = (1.2500, –0.9166,0.0666)'
E.) x(2) =
(-1,6250, 1.3125, –0.6562)
Transcribed Image Text:9. Find the solution vector of the given system by applying Gauss-Seidel method for 2 iterations with the intial vector x0) = (0,0,0)'. -2x1 + x2 +x3 = 4 X2 + 2x3 = 0 1 X1 – 2x2 -x3 = -4 A.) x(2) = (-1.0000, 1.0000, –0.5000) В) х(2) — (1.2500, —1.3333,0.6666)* C.) x2) = (-1.6250, –5.3750, 2.6875) D.) x(2) = (1.2500, –0.9166,0.0666)' E.) x(2) = (-1,6250, 1.3125, –0.6562)
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