Find the solution to this ancient Babylonian problem. There are two silver rings; = of the rst ring and + of the second ring are broken off, so that what is broken off weighs 1 sheqel. The rst diminished by its weighs as much as the second diminished by its . What did the silver rings originally weigh? [Hint: Consider the system of equations y 6x 10y 1, %3D %3D 7. 11 7 11 where x and y are the weights of the two rings.]
Find the solution to this ancient Babylonian problem. There are two silver rings; = of the rst ring and + of the second ring are broken off, so that what is broken off weighs 1 sheqel. The rst diminished by its weighs as much as the second diminished by its . What did the silver rings originally weigh? [Hint: Consider the system of equations y 6x 10y 1, %3D %3D 7. 11 7 11 where x and y are the weights of the two rings.]
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![Find the solution to this ancient Babylonian problem.
There are two silver rings; of the rst ring
and of the second ring are broken off, so
11
that what is broken off weighs 1 sheqel. The
rst diminished by its weighs as much as the
second diminished by its . What did the
silver rings originally weigh?
[Hint: Consider the system of equations
y
6x
10y
1,
%3D
7.
11
7
11
where x and y are the weights of the two rings.]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc6a1a6af-f1e4-4d78-8be0-18e762f871b4%2Fc6e1f483-eec0-49cc-90c5-c9c4c990f8e1%2F0wzjrjp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Find the solution to this ancient Babylonian problem.
There are two silver rings; of the rst ring
and of the second ring are broken off, so
11
that what is broken off weighs 1 sheqel. The
rst diminished by its weighs as much as the
second diminished by its . What did the
silver rings originally weigh?
[Hint: Consider the system of equations
y
6x
10y
1,
%3D
7.
11
7
11
where x and y are the weights of the two rings.]
![uty (*
= (x + y)² – 4xy to nd x -
Another Babylonian problem is
To the area of a rectangle, the excess of the
length over the width is added, giving 120%3;
moreover, the sum of the length and width is
24. Find the dimensions of the rectangle.
[Hint: The problem can be put in the form of two
equations xy +x - y = 120, x + y = 24; if the
substitution y = z – 2 is made, the system becomes
x +z = 26, xz = 144.]
P Type here to search](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc6a1a6af-f1e4-4d78-8be0-18e762f871b4%2Fc6e1f483-eec0-49cc-90c5-c9c4c990f8e1%2F0e5lws_processed.jpeg&w=3840&q=75)
Transcribed Image Text:uty (*
= (x + y)² – 4xy to nd x -
Another Babylonian problem is
To the area of a rectangle, the excess of the
length over the width is added, giving 120%3;
moreover, the sum of the length and width is
24. Find the dimensions of the rectangle.
[Hint: The problem can be put in the form of two
equations xy +x - y = 120, x + y = 24; if the
substitution y = z – 2 is made, the system becomes
x +z = 26, xz = 144.]
P Type here to search
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