Find the solution to each of these recurrence relations and initial conditions. Use an iterative approach.a) an = 3an−1, a0 = 2b) an = an−1 + 2, a0 = 3c) an = an−1 + n, a0 = 1d) an = an−1 + 2n + 3, a0 = 4e) an = 2an−1 − 1, a0 = 1f ) an = 3an−1 + 1, a0 = 1g) an = nan−1, a0 = 5h) an = 2nan−1, a0 = 1

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Q: or, Recurrence Formulae : ¨ (2n + 1) xP₂ = (n + 1) Pn+j+nP,-1 (n+1) Pn+1 = (2n + 1) xP₁ − nP,. -

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